The drive propeller of a ship starts from rest and accelerates at 2.65x10-3 rad/s2 for 2.36x103 s. For the next 1.02x103 s the propeller rotates at a constant angular speed. Then it decelerates at 2.82x 10-3 rad/s2 until it slows (without reversing direction) to an angular speed of 2.94 rad/s. Find the total angular displacement of the propeller.

Question
Asked Apr 3, 2019

The drive propeller of a ship starts from rest and accelerates at 2.65x10-3 rad/s2 for 2.36x103 s. For the next 1.02x103 s the propeller rotates at a constant angular speed. Then it decelerates at 2.82x 10-3 rad/s2 until it slows (without reversing direction) to an angular speed of 2.94 rad/s. Find the total angular displacement of the propeller.

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Expert Answer

Step 1

The problem can be split into three parts, acceleration phase, constant acceleration phase, deceleration phase. In the first case, the propeller of the ship accelerates at 2.65*10^-3 rad/s^2.

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Step 2

In the constant speed phase, equation 2 gives the angular displacement.

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Step 3

In the Deceleration phase, equation (4)...

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Rotational Mechanics

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