The efficiency of a Carnot cycle is Te ec =1- Th (a) If an engine operating between heat reservoirs at 293K and 473K extracts 1000 J per cycle from the hot reservoir, what is the maximum possible work that engine can do per cycle? (b) For this maximum work, how much heat is exhausted to the cold reservoir per cycle?

University Physics Volume 2
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Chapter4: The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 31P: If a refrigerator discards 80 J of heat per cycle and its coefficient of performance is 6.0, what...
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A Carnot cycle, consisting of an isothermal expansion and an adiabatic expansion, followed by
an isothermal compression and an adiabatic compression, is the most efficient form of a heat
engine.
M
AN
The efficiency of a Carnot cycle is
Te
ee =1-
Th
(a) If an engine operating between heat reservoirs at 293K and 473K extracts 1000 J per cycle
from the hot reservoir, what is the maximum possible work that engine can do per cycle?
(b) For this maximum work, how much heat is exhausted to the cold reservoir per cycle?
Transcribed Image Text:A Carnot cycle, consisting of an isothermal expansion and an adiabatic expansion, followed by an isothermal compression and an adiabatic compression, is the most efficient form of a heat engine. M AN The efficiency of a Carnot cycle is Te ee =1- Th (a) If an engine operating between heat reservoirs at 293K and 473K extracts 1000 J per cycle from the hot reservoir, what is the maximum possible work that engine can do per cycle? (b) For this maximum work, how much heat is exhausted to the cold reservoir per cycle?
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