The electric potential on a surface is given : V = 4me, Lª y where L is a constant with dimensions of length. Find the electric field vector at (x = 2, y = 3). O a. E= (12î – 6) O b. É (2î + 4§) %3D O c. E = 4 O d. É = Gi - 5) Ë = (-i+3)) е. f. E = (-3î – j) g. E = -4 O h. E = (-2î+ v3j) Ten L

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter26: Electric Potential
Section: Chapter Questions
Problem 76PQ: An electric potential exists in a region of space such that V = 8x4 2y2 + 9z3 and V is in units of...
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The electric potential on a surface is given :
V =
where Lis a constant with dimensions of length. Find the electric field vector at (x = 2, y = 3).
4me, L
O a. É = -4 (12î – 63)
Ten L
O b. É =
(2î + 4)
. E =
2 -
O d. E
Oe.
E =
O f. E = -4(-3î – î)
g.
E =
O h. E =
Te L*
-2î + v3j)
Transcribed Image Text:The electric potential on a surface is given : V = where Lis a constant with dimensions of length. Find the electric field vector at (x = 2, y = 3). 4me, L O a. É = -4 (12î – 63) Ten L O b. É = (2î + 4) . E = 2 - O d. E Oe. E = O f. E = -4(-3î – î) g. E = O h. E = Te L* -2î + v3j)
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