16. An electric field along x-axis is given as Ex = (4x' + 2x*)i, what is the voltage difference between x = 3 and x = 4? i.e. Find V4 - V3 = ? a. 200 V b. 250 V с. -200 V d. – 158 V е. 356 V If the electric potential in 3D space is given as V =x' +y + z - 6xy - 6 yz - 6zx 17. find the electric field vector, in i, j, k notation. а. Е%3D+(3x? - бу - 62)і — (Зу? - 6х-62)j + (32* — бу - бх)k b. Е%3D- (3x* - бу- 62)i + (3у? - бх — 62)jj - (32* - бу- бх)k с. Е%3D-(3x— бу - 62)і - (Зу - 6х - 62)j - (32- бу- бх)k d. E %3D +(3x2 - бу - 62)і + (Зу?- бх - 62)j + (32* - бу — бх)k 18. find the magnitude of the electric field at (2, 1,0). a. 19 v/m b. 20 v/m c. 23 v/m d. 21 v/m e. 22 v/m

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter26: Electric Potential
Section: Chapter Questions
Problem 76PQ: An electric potential exists in a region of space such that V = 8x4 2y2 + 9z3 and V is in units of...
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16. An electric field along x-axis is given as Ex = (4x' + 2x)i, what is the voltage difference between x
= 3 and x = 4? i.e. Find V4 – V3 = ?
а. 200 V
b. 250 V
с. -200 V
d. – 158 V
е. 356 V
3
If the electric potential in 3D space is given as V = x' + y° + z° - 6xy - 6 yz - 6zx
17. find the electric field vector, in i, j, k notation.
а. Е %3D +(3x - бу -62)і — (3у? — бх — 62)ј + (3z - бу — бх)k
b. Е %3D - (3x? - бу- 62)і + (3у - бх — 62)ј — (3z* -бу- бх)k
с. Е 3 - (3x*- бу - 62)і — (3у- 6х - 62)j — (32* — бу - 6х)k
d. E 3D +(3x* - бу- 6z)і + (3у? - бх - 62)ј + (3z* - бу - 6х)k
18. find the magnitude of the electric field at (2, 1, 0 ).
а. 19 v/m
b. 20 v/m
с. 23 v/m
d. 21 v/m
e. 22 v/m
Transcribed Image Text:87% 12:13 PM 16. An electric field along x-axis is given as Ex = (4x' + 2x)i, what is the voltage difference between x = 3 and x = 4? i.e. Find V4 – V3 = ? а. 200 V b. 250 V с. -200 V d. – 158 V е. 356 V 3 If the electric potential in 3D space is given as V = x' + y° + z° - 6xy - 6 yz - 6zx 17. find the electric field vector, in i, j, k notation. а. Е %3D +(3x - бу -62)і — (3у? — бх — 62)ј + (3z - бу — бх)k b. Е %3D - (3x? - бу- 62)і + (3у - бх — 62)ј — (3z* -бу- бх)k с. Е 3 - (3x*- бу - 62)і — (3у- 6х - 62)j — (32* — бу - 6х)k d. E 3D +(3x* - бу- 6z)і + (3у? - бх - 62)ј + (3z* - бу - 6х)k 18. find the magnitude of the electric field at (2, 1, 0 ). а. 19 v/m b. 20 v/m с. 23 v/m d. 21 v/m e. 22 v/m
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