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- We are presented with a particle of mass (m = 4.56 kg) which is in uniform circular motion going around a fixed point O. It had a radius of orbit (r = 3.63 m) and it experiences a net force of magnitude F = Br toward the fixed point O, where B = 2.75 Nm. What is the period of the particles orbit?At the Earth's surface a projectile is launched straight up at a speed of 10.0 km/s. To what height will it rise?(the radius of earth is 6.37*10^6)A particle is moving in an elliptical path and its motion is described by the following equations? = ? ???ℎ?. ???? ??? ? = ? ???ℎ? ???? (? ≥ 0 ??? 0 ≤ ? ≤ 2?)Where a is constant. Find kinetic energy of the particle
- The speed of a person standing on the equator, due to the earth's rotation.A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 251 kg. A small boy of mass m = 42 kg runs tangentially to the merry-go-round at a speed of v = 1.2 m/s, and jumps on. Randomized Variables R = 1.3 metersM = 251 kgm = 42 kgv = 1.2 m/s a)Calculate the moment of inertia of the merry-go-round, in kg ⋅ m2. b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy.A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 251 kg. A small boy of mass m = 42 kg runs tangentially to the merry-go-round at a speed of v = 1.2 m/s, and jumps on. Randomized Variables R = 1.3 metersM = 251 kgm = 42 kgv = 1.2 m/s a) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry go round? b) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy is at the center of the merry go round? c)Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the…
- A ball rolls on a circular track of radius 0.62 m with a constantangular speed of 1.3 rad>s in the counterclockwise direction. If theangular position of the ball at t = 0 is u = 0, find the x component of the ball’s position at the times 2.5 s, 5.0 s, and 7.5 s. Letu = 0 correspond to the positive x direction.We place a 2.0 m long rod in a vertical position and let it fall. At what speed does the upper end of the rod fly against the horizontal floor, if its lower end doesnt move anywhere? (The solution is 7.7 m / s)A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 291 kg. A small boy of mass m = 42 kg runs tangentially to the merry-go-round at a speed of v = 1.8 m/s, and jumps on. Randomized VariablesR = 1.3 metersM = 291 kgm = 42 kgv = 1.8 m/s Part A- Calculate the moment of inertia of the merry-go-round, in kg ⋅ m2. Part B- Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. Part C- Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. Part D- The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry…
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