The equilibrium constant for the autoionization of water at 25 °C is 1,00 X 1014 H2O (1) = H (aq) + OH (aq) The DH° is 55.8 kJ/mol. Determine the equilibrium constant at 45.8 °C answer in the form: X 10 14

The equilibrium constant for the autoionization of water at 25 °C is 1,00 X 1014 H2O (1) = H (aq) + OH (aq) The DH° is 55.8 kJ/mol. Determine the equilibrium constant at 45.8 °C answer in the form: X 10 14

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 50P

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Question

The equilibrium constant for the autoionization of water at 25 °C is 1.00 X 1014
H2O (1) =
H (aq)+ OH (aq)
The DH° is 55.8 kJ/mol. Determine the equilibrium constant at 45.8 °C
answer in the form:
X 10 14

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