The equilibrium constant for the reaction A(g) + 2B(g) → 3C(g) is 12.3 at 975 K.  a. Calculate the ∆G°, kJ/mol, for the reaction at the given temperature. b. Calculate the ∆G, kJ/mol, for the reaction when the concentrations are: [A] = 0.755 M, [B] = 0.600 M, and [C] = 0.250 M at the same temperature.

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
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The equilibrium constant for the reaction A(g) + 2B(g) → 3C(g) is 12.3 at 975 K. 
a. Calculate the ∆G°, kJ/mol, for the reaction at the given temperature.
b. Calculate the ∆G, kJ/mol, for the reaction when the concentrations are: [A] = 0.755 M,
[B] = 0.600 M, and [C] = 0.250 M at the same temperature.

Expert Solution
Step 1

The equilibrium reaction given is,

=> A (g) + 2 B(g) --------> 3 C (g)                                            Keq = 12.3 

Given : Temperature = 975 K

 

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