N2 (g) + 3H2 ↔ 2NH3 The standard free energy change at 500 Kelvins is -33.2 kj / mol and the equilibrium constant K = 6.59x105 if the initial conditions in an experiment are P (H2) = 0.25 atm, P (N2) = 0.87 atm and P (NH3) = 12.9 atm Comment on the direction of the reaction by calculating ∆G for the reaction under these conditions. Products Entrants Just write "1 or 2" for the answer.

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
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N2 (g) + 3H2 ↔ 2NH3 The standard free energy change at 500 Kelvins is -33.2 kj / mol and the equilibrium constant K = 6.59x105 if the initial conditions in an experiment are P (H2) = 0.25 atm, P (N2) = 0.87 atm and P (NH3) = 12.9 atm Comment on the direction of the reaction by calculating ∆G for the reaction under these conditions. Products Entrants Just write "1 or 2" for the answer.
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