Question
Asked Jul 31, 2019
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  1. The equilibrium constant, Kp, for the following reaction is 6at 698 K.

    H2(g) + I2(g) 2HI(g)


    If ΔH° for this reaction is -10.4 kJ, what is the value of Kp at 603 K?

    Kp = 
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Expert Answer

Step 1

To calculate Kp at 603 K, the following expression can be used,

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-AHo In Ti R T2 Ki 6, TI 698 K, T2 603 K AHo 10.4 x 1000 J, R = 8.314 J/mol-K

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Step 2

Substituting the values in the ...

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(-10400) К2 In 698 8.314 603 K2 7.95

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Chemical Thermodynamics

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