The equilibrium constant, K, for a redox reaction is related to the standard cellpotential, E. by the equationStandard reduction potentialsIn K =nFEReduction half-reactionE (V)RTAg+(ag) +eAg(s)0.80where n is the number of moles of electrons transferred, F (the Faraday's constant)is equal to 98 500 C mol-1, R(the gas constant) is equal to 8.314 JK-' mol1.and T is the Kelvin temperature.Cu2+ (ag) + 20Cu(s)0.34Sn+(ag) + 4e-Sn(s)0.152H+(ag) + 20H2(9)Ni+ (ag) + 2e-»Ni(s)Fe+ (ag) + 20Fe(s)Zn2+ (ag) + 2e→Zn(s)-0.26-0.45-0.76A1+ (ag) + 30-Al(s)-1.68Mg+ (ag) + 20MB(s)2.37• Part AUse the table of standard reduction potentials given above to calculate the equilibrium constant at standard temperature (25 °C) for the following reaction:Fe(s) + N+ (ag) »Fe2+ (ag) + Ni(s)Express your answer numerically.> View Available Hint(s)?K = Part BCalculate the standard cell potential (Ecel for the reactionX(s) +Y*(ag) X+(ag) + Y(s)if 6.51 x 10 .Express your answer to three significant figures and include the appropriate units.• View Available Hint(s)HA?ValueUnitsSubmit

Part (A) : Temperature , T =25°C=(25+273)K=298 K Given reaction is : Fe(s) + Ni2+ (aq) →Fe2+ (aq) +…

The equilibrium constant, K. for a redox reaction is related to the standard cell potential, E by the equation cell nFE In K cel RT where n is the number of moles of electrons transferred, F (the Faraday's constant) is equal to 98 500 C mol. R (the gas constant) is equal to 8.314 JKmol and Tis the Kelvin temperature.

The equilibrium constant, K. for a redox reaction is related to the standard cell potential, E by the equation cell nFE In K cel RT where n is the number of moles of electrons transferred, F (the Faraday's constant) is equal to 98 500 C mol. R (the gas constant) is equal to 8.314 JKmol and Tis the Kelvin temperature.

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter32: Voltaic Cell Measurements

Section: Chapter Questions

Problem 2ASA

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