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The equilibrium constant, Ke, for the following reaction is 0.0129 at 600 K. COC12 (g) CO(g) + Cl₂(g) If an equilibrium mixture of the three gases in a 15.7 L container at 600 K contains 0.436 mol of COC1₂(g) and 0.321 mol of CO, the equilibrium concentration of Cl₂ is M.

The equilibrium constant, Ke, for the following reaction is 0.0129 at 600 K. COC12 (g) CO(g) + Cl₂(g) If an equilibrium mixture of the three gases in a 15.7 L container at 600 K contains 0.436 mol of COC1₂(g) and 0.321 mol of CO, the equilibrium concentration of Cl₂ is M.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.56QE
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The equilibrium constant, Ke, for the following reaction is 0.0129 at 600 K. COC1₂(g) → CO(g) + Cl₂ (g) If an equilibrium mixture of the three gases in a 15.7 L container at 600 K contains 0.436 mol of COC1₂ (g) and 0.321 mol of CO, the equilibrium concentration of Cl₂ is M.
Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 0.0129 at 600 K. COC1₂(g) → CO(g) + Cl₂ (g) If an equilibrium mixture of the three gases in a 15.7 L container at 600 K contains 0.436 mol of COC1₂ (g) and 0.321 mol of CO, the equilibrium concentration of Cl₂ is M.
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