The figure shows a setup where when the member AB is horizontal and the unstretched aluminum bar length 2 m is attached to end D, the steel bar A has a gap of 3 mm with the support at C as shown by A in the figure. At that point the system is deformed and the steel bar is attached to the support C. After this is done and all external forces are removed compute (a) the forces in both the steel and the aluminum bars. 0.75 m 1.5 m

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.3.27P: A 150-lb rigid bar AB. with friction less rollers al each end. is held in the position shown in the...
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The figure shows a setup where when the member AB is horizontal and the unstretched aluminum bar length 2 m is attached to end D, the
steel bar A has a gap of 3 mm with the support at Cas shown by A in the figure. At that point the system is deformed and the steel bar is
attached to the support C. After this is done and all external forces are removed compute (a) the forces in both the steel and the aluminum
bars.
0.75 m
1.5 m
Steel
A = 250 mm?
E = 200 GPa
Aluminum
L= 2 m
A = 300 mm
E = 70 GPa
Figure P-242
Transcribed Image Text:The figure shows a setup where when the member AB is horizontal and the unstretched aluminum bar length 2 m is attached to end D, the steel bar A has a gap of 3 mm with the support at Cas shown by A in the figure. At that point the system is deformed and the steel bar is attached to the support C. After this is done and all external forces are removed compute (a) the forces in both the steel and the aluminum bars. 0.75 m 1.5 m Steel A = 250 mm? E = 200 GPa Aluminum L= 2 m A = 300 mm E = 70 GPa Figure P-242
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