NEED HELP WITH THIS PRACTICE QUESTION EnteredAnswer PreviewResultMessage[e^(7*t)]*i+5*cos(8*t)*j+5*sqrt(8*t)*ke7ti + 5 cos(8t) j+5/8tkincorrectThe domain of your function doesn't match that of the correct answer49*[e^(7*t)]*i-320*sin(8*t)*j-320*sin(8*t)*k49ei – 320 sin(8t) j – 320 sin(8t) kincorrect40.640.6correctThe first coordinate is incorrect7i+40k7i + 40kincorrectThe third coordinate is incorrectThe equation F(t)(e7t) i + (5 cos(8t)) j+ (5 sin(8t)) k gives the position of a particle in space at time t. Find the particle's velocity and acceleration vectors at timet. Then find the particle's speed and direction at time t = 0.v(t)= (e^(7t))i+(5cos(8t)j)+(5sqrt(E Ea(t) = (49e^(7t))i-(320sin(8t))j-320:Speed at time t = 0 is 40.6Direction at time t = 0 is 7i+40k

Name: NEED HELP WITH THIS PRACTICE QUESTION EnteredAnswer PreviewResultMessa
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: NEED HELP WITH THIS PRACTICE QUESTION EnteredAnswer PreviewResultMessage[e^(7*t)]*i+5*cos(8*t)*j+5*sqrt(8*t)*ke7ti + 5 cos(8t) j+5/8tkincorrectThe domain of your function doesn't match that of the correct answer49*[e^(7*t)]*i-320*sin(8*t)*j-320*sin(8

Answered: Image /qna-images/answer/59d04b3a-55b8-4150-bc6f-da53d52eac52.jpg

Answered: The first coordinate is incorrect 40k…

Math

Calculus

The first coordinate is incorrect 40k incorrect The third coordinate is incorrect

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.2: Graphs Of Equations

Problem 78E

See similar textbooks

Similar questions

Determine dimension x to 3 decimal places.
Prove cosh 2 x - sinh 2 x =1
1:prove that cosh^2x-sinh^2x=1 2: prove that (sinhx-coshx)^n = sinhnx-coshnx
suppose that cosx<=1 for all x>=0.Combine this with the first fundamental theorem of calculus to prove sinx<=x ,1-cosx<=x^2/2 for all x>=0.USe the same idea to prove x-sinx<=x^3/6 &x-x^3/6<=sinx<=x for all x>=0
6 From algebraic form of function ez, prove that |ez| = ex
Find the linearization of ƒ(x) = sqrt(x + 1) + sin x at x = 0. How is it related to the individual linearizations of sqrt(x + 1) and sin x at x = 0?
How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read it
solve using L'Hopital's Rule 3. Lim (ex + e-x - x2 - 2) / (sin2x - x2) x->0
Express f(theta) where f(theta)=cos theta - square root of 3 sin theta in the form Rcos (theta +lambda) where R> 0 and lambda is an acute angle Hence find the max and minimum value of 5/f(theta)+7 showing all steps
solve using L'Hopital's Rule 7. Lim 1/(tan-1)2 - 1/x2 x->0
Prove sech 2 x =1 - tanh 2x
How would you rewrite this when applying the least common dominator rule for( -sin t/cos t) + (cos t/1-sin t)