The following code is printing the result None . We are expecting it to print 10 . What do we need to change? def multiply(a, b): # (A) a * b # (B) print(multiply(5,2)) # (C)
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- C++ Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows: If N is an even number, then divide N by two to get a new value for N If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. Continue to generate numbers in this way until N becomes equal to 1 For example, starting from N = 3 the complete ’3N+1’ sequence would be: 3, 10, 5, 16, 8, 4, 2, 1 Write code to ask the user to enter a positive integer (N) in the main() function. Write a function sequence() that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that was received (entered by the user). The function must also count and return the numbers that the sequenceconsists of. The returned value must be displayed from the main() function.Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…Code language Java 1, Add a print statement to say “Multiplication Table” and then prompt theuser to enter an integer. Your program should then prints “times table” for thenumbers from 1 to the given integer (inclusive). That is, for input n, you would printa table of n rows (lines) each with n columns, where the cell at row i and columnj contains the value i × j. You do need separate rows, but don’t worry about thecolumns lining up nicely yet. 2. Add a print statement to say “Prime Testing”.Using the integer entered by the user above, print out all the prime numbers between2 and the number squared. E.g., if the user types 12 for the multiplication table part,you should print all the prime numbers that are not larger than 144.All integers are either prime or composite. A prime number is one that has no integerfactors other than itself or one. Examples are 2, 3, 5, 7, 11, 13, . . .. A compositenumber, by contrast, has multiple factors. Examples are 4, 6, 12, 15, 18, 21, . . ..Testing…
- Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…Do not use static variables to implement recursive methods. USING JAVA Indicate the order of the following growth functions using < (e.g. n < n2) n2 log n n n2/ log n n! (1.5)n 3nWrite a code to find prime numbers between 100 and 200 Write a code which find power of number from 1 to n Example 2 raise to power 0 = 1 2 raise to power 1 = 2 2 raise to power 2 = 4 2 raise to power 3 = 8 2 raise to power 4 = 16 2 raise to power 5 = 32
- main(){int i,n; for(int i=0;i<n;i++){fork();printf("*");}}How many times ‘*’ will be printed?Create the generated machine code from snippet code as follow: int i=10, j, x;for (a=10; a>0; a--) {if (a % 2 == 1) i += a;else i /= 2;j = i*2;}x = i+j; please solve max in 30 minutes thank uThis Code print the first occurrences of x, Modify the code to print the last occurrences of x and print how many times it exists? ( with explanation for each line if possible) many thanks.
- in phython langauge: Write a program which reads the number of blocks the builders have,and outputs the height of the pyramids that can be built using these blocks.C++ Given an integer num, repeatedly add all its digits until the result has only one digit, and return it. Example 1: Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it. Example 2: Input: num = 0 Output: 0 Constraints: 0 <= num <= 231 - 1 Follow up: Could you do it without any loop/recursion in O(1) runtime? //code here class Solution {public: int addDigits(int num) { }}; //The following code examines two variables -- x and y -- and prints the largest odd number among them. If none of them is odd, it prints a message to that effect. def largestOdd(x,y): """ x and y are numbers Returns the maximum odd number of x and y. If they all are even, return None """ foundOdd = False largest = 0 if x % 2 == 1 : largest = x foundOdd = True if y % 2 == 1 : if not foundOdd : largest = y foundOdd = True elif y > largest : largest = y if foundOdd : return largest else : return None Assume that largestOdd is called with numbers as arguments.Which of the following test suites would make a path-complete glass box test suite for largestOdd? Question 6 options: Test Suite A: foundOdd(2,4), foundOdd(2,5), foundOdd(11,12), foundOdd(11,13), foundOdd(11,7) Test Suite B: foundOdd(2,4), foundOdd(2,6), foundOdd(11,12),…