The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B P 20 44 50 30 26 30 Test for independence of the row and column variables using a = 0.05 . Compute the value of the x test statistic (to 2 decimals). Use Table 3 of Appendix B to find the p-value. The p-value is between 0.01 and 0.025 What is your conclusion? Conclude the row variable and column variable are not independent
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- A major credit card company is investigating whether the distribution of the number of credit cards used by its customers has changed from last year to this year. Customers are classified as using 1 card, 2 cards, or more than 2 cards. The company conducts a chi-square goodness-of-fit test to investigate whether there is a change in the distribution of number of cards used from last year to this year. The value of the chi-square test statistic was χ2=7.82χ2=7.82 with a corresponding pp-value of 0.02. Assuming the conditions for inference were met, which of the following is the correct interpretation of this pp-value?Comfort Food Magazine states the average calories of a medium size hot dog is 209. The number of calories for a medium size hot dog is normally distributed. A random sample of 15 different brands of medium size hot dogs resulted in the following calorie count provided below. Can it be concluded that the average calories of a medium size hot dog will be 209 based on level significance of 0.01?A high school principal wanted to know if there was a difference in absences for 9th grade, 10th grade, 11th grade, or 12th grade among students with less than a 2.0 GPA. She took a random sample of n = 5 students from each grade and compared absences among the four grades using ANOVA. The data are below: 9th grade 10th grade 11th grade 12th grade 6 9 6 7 7 10 12 11 11 14 17 8 11 14 15 15 16 12 12 12 9. Calculate the F statistic 10. Using the table in the back of the book, find the critical value for F (Fcrit) with α = .05 11. Calculate the Tukey HSD (using α = .05)
- A major credit card company is investigating whether the distribution of the number of credit cards used by its customers has changed from last year to this year. Customers are classified as using 1 card, 2 cards, or more than 2 cards. The company conducts a chi-square goodness-of-fit test to investigate whether there is a change in the distribution of number of cards used from last year to this year. The value of the chi-square test statistic was χ2=7.82 with a corresponding p-value of 0.02. Assuming the conditions for inference were met, which of the following is the correct interpretation of this p-value? There is a 2 percent chance that the company’s claim is correct. A There is a 2 percent chance of obtaining a chi-square value of at least 7.82. B If the null hypothesis were true, there is a 2 percent chance of obtaining a chi-square value of at least 7.82. C If the null hypothesis were true, there is a 2 percent chance that the company’s claim is…The manufacturer of a new eye cream claims that the cream reduces the appearance of fine lines and wrinkles after just 1414 days of application. To test the claim, 1010 women are randomly selected to participate in a study. The number of fine lines and wrinkles that are visible around each participant’s eyes is recorded before and after the 1414 days of treatment. The following table displays the results. Test the claim at the 0.050.05 level of significance assuming that the population distribution of the paired differences is approximately normal. Let women before the treatment be Population 1 and let women after the treatment be Population 2. Number of Fine Lines and Wrinkles Before 12 11 10 14 12 9 12 14 9 12 After 13 8 6 14 11 6 13 11 5 11 Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.