The free energy change for the following reaction at 25 °C, when [H+] = 1.11 M and [Sn2+] = 1.21x10-3 M, is -43.9 kJ: 2H*(1.11 M) + Sn(s)→ H2(g) + Sn2+(1.21x10-3 M) AG = -43.9 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction v forward

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter18: Electrochemistry
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Problem 18.44QE: For each of the reactions, calculate E from the table of standard potentials, and state whether the...
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The free energy change for the following reaction at 25 °C, when [H*] = 1.11 M and [Sn2+] = 1.21x10-3 M, is -43.9
%3D
kJ:
2H*(1.11 M) + Sn(s) H2(g) + Sn2+(1.21x10-3 M)
AG = -43.9 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction v
forward
reverse
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [H*] = 1.11 M and [Sn2+] = 1.21x10-3 M, is -43.9 %3D kJ: 2H*(1.11 M) + Sn(s) H2(g) + Sn2+(1.21x10-3 M) AG = -43.9 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction v forward reverse
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