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The free energy change for the following reaction at 25 °C, when [Pb2+] 6.68x10-3 M, is -368 k): = 1.13 M and [Cr3+] = %3D 3P62+(1.13 M) + 2Cr(s)3Pb(s) + 2Cr3+(6.68x10-3 M) AG = -368 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? forward reverse

The free energy change for the following reaction at 25 °C, when [Pb2+] 6.68x10-3 M, is -368 k): = 1.13 M and [Cr3+] = %3D 3P62+(1.13 M) + 2Cr(s)3Pb(s) + 2Cr3+(6.68x10-3 M) AG = -368 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? forward reverse

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 27Q: The free energy change for a reaction, G, is an extensive property. What is an extensive property?...
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The free energy change for the following reaction at 25 °C, when [Pb2+] = 1.13 M and [Cr3+]%3D 6.68x10-3 M, is -368 k): %3D 3PB2+(1.13 M) + 2Cr(s) 3Pb(s) + 2Cr3+(6.68x10-3 M) AG = -368 kJ What is the cell potential for the reaction as written under these conditions? Answer: V. Would this reaction be spontaneous in the forward or the reverse direction? forward reverse
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Pb2+] = 1.13 M and [Cr3+]%3D 6.68x10-3 M, is -368 k): %3D 3PB2+(1.13 M) + 2Cr(s) 3Pb(s) + 2Cr3+(6.68x10-3 M) AG = -368 kJ What is the cell potential for the reaction as written under these conditions? Answer: V. Would this reaction be spontaneous in the forward or the reverse direction? forward reverse
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