The great, great grandparents of one of your classmates sold their factory to the government 104 years ago for $150,000. If these proceeds had been invested at 6%, how much would this legacy be worth today? Assume annual compounding. 2. A friend who owns a perpetuity that promises to pay $1,000 at the end of each year, forever, comes to you and offers to sell you all of the payments to be received after the 25th year for a price of $1,000. At an interest rate of 10%, should you pay the $1,000 today to receive payment numbers 26 and onwards? What does this suggest to you about the value of perpetual payments?

The great, great grandparents of one of your classmates sold their factory to the government 104 years ago for $150,000. If these proceeds had been invested at 6%, how much would this legacy be worth today? Assume annual compounding. 2. A friend who owns a perpetuity that promises to pay $1,000 at the end of each year, forever, comes to you and offers to sell you all of the payments to be received after the 25th year for a price of $1,000. At an interest rate of 10%, should you pay the $1,000 today to receive payment numbers 26 and onwards? What does this suggest to you about the value of perpetual payments?

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter2: Chemical Formulas, Equations, And Reaction Yields

Section: Chapter Questions

Problem 46AP

See similar textbooks

Similar questions

In the synthesis of benzoic acid, 3.5 mL of toluene were used and mixed with potassium permanganate solution. In making the potassium permanganate solution, 7 grams of the powder were dissolved in 150 mL of water. The resulting crystals were purified and the yield 1.53 grams. Identify the limiting reagent and compute for the number of moles that it consumed. What is the theoretical yield? What is the percentage yield? MW toluene = 94.14, density=0.87 g/mL , MW KMnO4 = 158, density = 2.7 g/mL , MW Benzoic acid = 122, density = 1.27 g/mL
End-of-the-Pipe Control versus Pollution Prevention The marginal cost of reduction curve illustrated in Figure 4.5 assumes a particular approach to reducing pollution, often called end-of-the-pipe control. In other words, when we draw that upward-sloping MC curve, we assume that firms respond to regulation by maintaining the same basic production technology but adding on scrubbers or filters to clean up their emissions. Under these conditions, rising marginal costs of reduction are quite likely. However, suppose that firms radically overhaul their production technology, so that they completely eliminate emissions. This is known as a “pollution prevention” strategy. An example might be a jeweler, who in the face of regulation adopts a closed-loop production system. This is one in which all mineral waste products are recovered from recycled wastewater and then reused. What would the marginal cost of reduction diagram look like in this case? a. Specifically, assume that…
In the background reading, it was pointed out that heroin can be produced from morphine in a manner similar to synthesis performed in this experiment. The balanced equation for the synthesis of heroin is given below. How many grams of heroin can be produced by the reaction of 20.00 grams of morphine and 10.00 ml of acetic anhydride? C17H19NO3 + 2 C4H6O3  C21H23NO5 + 2 HC2H3O2 Morphine Acetic Anhydride Heroin Acetic Acid
balancing equations C2H6+O2=CH3COOH+H2O
In the body, the amino acid valine C5H11NO2(aq)C5H11NO2(aq)reacts with oxygen gas to produce gaseous carbon dioxide, liquid water, and urea, CH4N2O(aq)CH4N2O(aq).
Show your work: Balance the following chemical equation: C7H16O5 + O2 ---> CO2 + H2O
Your body deals with excess nitrogen by excreting it in the form of urea, NH2CONH2. The reaction producing it is the combination of arginine (C6H14N4O2) with water to give urea and ornithine (C5H12N2O2). C6H14N4O2 + H2O ? NH2CONH2 + C5H12N2O2 [Molar masses: 174.2 18.02 60.06 132.2] If you excrete 95 mg of urea, what quantity of arginine must have been used? What quantity of ornithine must have been produced?
You have recently been hired as a researcher in a premier university. Your research deals with isolating novel antibiotics from Streptomyces species to offer solution in the growing problem of antibiotic resistance. Unfortunately, late one night you did not label the tubes and plates clearly. Now your promising work needs to be resolved with only a few of information retained. Gladly, you found the results in your notebook. Unfortunately, they are not labeled either. These graphs represent percentage of survival of bacteria after treatment with the antibiotics. Samples with antibiotic added (black bars); controls with no antibiotic added (grey bars). You need to identify which antibiotic was used per set-up (see figure). Listed below are some essential information. Antibiotic A: 0.5 kDa protein, targets peptidoglycanAntibiotic B: 20 kDa protein, targets peptidoglycanAntibiotic C: Cationic antimicrobial peptideAntibiotic D: Targets lipopolysaccharide Staphylococcus aureus: gram-positive…
Congratulations, you have just been hired at a local laboratory. Your first task is to prepare 10.0 mL of a 1.50 x 10-6 M solution of a small protein (FW: 3600 g/mole). Available to you are an electronic balance that is accurate to the nearest 0.001 g, a 1.00-mL pipette, and 10-mL volumetric flasks. Describe how to prepare the desired solution. (Note that the amount of protein is so small that you will need to make a more concentrated stock solution and dilute it.)
3TiO2(s) + 4C(s) +6C2(g) -------à 3TiC4(g) 2CO2(g) + 2CO(g) a. If the reactor contains 11.34 g C, 13.56 g Cl2, and 8.3 g TiO2, identify the limiting reagent.
The atomic hydrogen exists in space at an estimated concentration of one particle per cubic meter. If the collision diameter is 2.5 ×10^(–10) meter and the temperature is 2.7 Kelvin, how many kilometers away will the next potential collision be? Express the answer in three significant figures.
The analysis of a product of combustion on dry basis, when C6H18 was burned with atmospheric air, is as follows: CO2=12%, CO=1.75%, O2=3.01%, N2=83.24%. Compute the actual air-fuel ratio.