KEY IDEAS The long solenoid S shown (in cross section) in Fig. 30-3 has 220 turns/cm and carries a current i 1.5 A; its diameter D is 3.2 cm. At its center we place a 130-turn closely packed coil C of diameter d 2.1 cm. The current in the solehoid is reduced to zero at a steady rate in 25 ms. What is the magni- tude of the emf that is induced in coil C while the current in the solenoid is changing? 1. Because it is located in the interior of the solenoid, coil C lies within the magnetic field produced by current i in the solenoid; thus, there is a magnetic flux , through coil C. 2. Because current i decreases, flux , also decreases, 3. As Pn decreases, emf & is induced in coil C. 4. The flux through each turn of coil C depends on the area A and orientation of that turn in the solenoid's magnetic field B.Because B is uniform and directed perpendicular to area A, the flux is given by Eq. 30-2 ( BA). 5. The magnitude B of the magnetic field in the interior of a solenoid depends on the solenoid's current i and its number n of turns per unit length, according to Eq. 29-23 (B=Hin). 20000 Axis Figure A coil Cis located inside a solenoid S, which carries current i.

Principles of Physics: A Calculus-Based Text
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Chapter23: Faraday’s Law And Inductance
Section: Chapter Questions
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Q8: Faraday's Law
KEY IDEAS
The long solenoid S shown (in cross section) in Fig. 30-3 has
220 turns/cm and carries a current i = 1.5 A; its diameter D
is 3.2 cm. At its center we place a 130-turn closely packed
coil C of diameter d 2.1 cm. The current in the solehoid is
reduced to zero at a steady rate in 25 ms. What is the magni-
tude of the emf that is induced in coil C while the current in
the solenoid is changing?
1. Because it is located in the interior of the solenoid, coil C
lies within the magnetic field produced by current i in the
solenoid; thus, there is a magnetic flux d, through coil C.
2. Because current i decreases, flux also decreases.
3. As d decreases, emf E is induced in coil C.
4. The flux through each turn of coil C depends on the area
A and orientation of that turn in the solenoid's magnetic
field B.Because B is uniform and directed perpendicular
to area A, the flux is given by Eq. 30-2 (4 = BA).
5. The magnitude B of the magnetic field in the interior of
a solenoid depends on the solenoid's current i and its
number n of turns per unit length, according to Eq. 29-23
(B = Pin).
Axis
Figure A coil Cis located inside a solenoid S, which carries
ent i.
Transcribed Image Text:Q8: Faraday's Law KEY IDEAS The long solenoid S shown (in cross section) in Fig. 30-3 has 220 turns/cm and carries a current i = 1.5 A; its diameter D is 3.2 cm. At its center we place a 130-turn closely packed coil C of diameter d 2.1 cm. The current in the solehoid is reduced to zero at a steady rate in 25 ms. What is the magni- tude of the emf that is induced in coil C while the current in the solenoid is changing? 1. Because it is located in the interior of the solenoid, coil C lies within the magnetic field produced by current i in the solenoid; thus, there is a magnetic flux d, through coil C. 2. Because current i decreases, flux also decreases. 3. As d decreases, emf E is induced in coil C. 4. The flux through each turn of coil C depends on the area A and orientation of that turn in the solenoid's magnetic field B.Because B is uniform and directed perpendicular to area A, the flux is given by Eq. 30-2 (4 = BA). 5. The magnitude B of the magnetic field in the interior of a solenoid depends on the solenoid's current i and its number n of turns per unit length, according to Eq. 29-23 (B = Pin). Axis Figure A coil Cis located inside a solenoid S, which carries ent i.
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