University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter9: Condensed Matter Physics
Section: Chapter Questions
Problem 80P: What is the critical magnetic field for lead at T = 2.8 K?
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Question
The magnetic field of a wave is given by:
Image
Determine the expression for the electric field of the
![2π
B = 6 x 10-6 sen 6 x 108t +: + x) k [7]
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F062b1c77-305d-409c-81c8-db6135ac7ea3%2F2d6b04d9-5807-437b-a87e-4bba8bcc834e%2Fz60q5lk_processed.png&w=3840&q=75)
Transcribed Image Text:2π
B = 6 x 10-6 sen 6 x 108t +: + x) k [7]
2
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O b. E= 900 sen [6 × 10³t+ 2x] (î)
O c. Ē = 900 sen[6 × 10³t+ 2x](î)
O d. Ninguna de las opciones.
○ e. E = 1800 sen[6 × 10³t + 4x](−Ê)
O f. E = 1800 sen [6 × 10³t+ 2x](-3)
O g. E= 1800 sen[6 × 10³t + 4x](−î)
○ h. Ē = 900 sen[6 × 10³t+ 4x](î)](https://content.bartleby.com/qna-images/question/062b1c77-305d-409c-81c8-db6135ac7ea3/10847b25-5da2-4a4b-9430-748b9e8ec84c/u7eftwp_processed.png)
Transcribed Image Text:Seleccione una:
O a. E=1800 sen[6 × 10®t+2x](−ê)
O b. E= 900 sen [6 × 10³t+ 2x] (î)
O c. Ē = 900 sen[6 × 10³t+ 2x](î)
O d. Ninguna de las opciones.
○ e. E = 1800 sen[6 × 10³t + 4x](−Ê)
O f. E = 1800 sen [6 × 10³t+ 2x](-3)
O g. E= 1800 sen[6 × 10³t + 4x](−î)
○ h. Ē = 900 sen[6 × 10³t+ 4x](î)
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