The main focus of this article is to discuss some qualitative behavior of the solutions of the nonlinear difference equation a1ym-1 + a2ym-2a3Ym-3 + a4Ym-4+a5Ym-5 B1ym-1 + 2ym-2 +B3Ym-3 + B4Ym-4 + B5Ym-5 Ym+1 = = Aym+· m = 0, 1, 2, ..., (1.1)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The main focus of this article is to discuss some qualitative behavior of
the solutions of the nonlinear difference equation
a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5
Ym+1 =
Aym+
т 3D 0, 1, 2, ...,
В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5
(1.1)
Transcribed Image Text:The main focus of this article is to discuss some qualitative behavior of the solutions of the nonlinear difference equation a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5 Ym+1 = Aym+ т 3D 0, 1, 2, ..., В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5 (1.1)
2 The local stability of the solutions
In this section, the local stability of the solutions of Eq.(1.1) is investigated.
The equilibrium point ỹ of Eq.(1.1) is the positive solution of the equation
i=1
ỹ = Aỹ +
(2.6)
E-1 Bi
Then, the only positive equilibrium point ỹ of Eq.(1.1) is given by
Li=1
(2.7)
(1 – A) ( E)
55
provided that A < 1. Nơw, let us introduce a continuous function
(0, 0)6 → (0, ∞) which is defined by
H :
H(uo, ..., u5) = Auo +
(2.8)
Therefore, it follows that
H(u0,...,u5)
= A,
H(u0,...,us)
a1 E(B;u;)] – B1 [E2la;u;)]
H(uo,...,u5)
H(uo,...,u5)
duz
H(u0,...,u5)
a4 (E-1(Biu;)+Bsus] – Ba [Ei-1(asu;)+agus]
H(u0,...,u5)
Əug
a5
Consequently, we get
8H(ỹ,.î) = A=- P5,
duo
(1–4)[a1 ( , Bi) – B1 (Ea)]
= - P4,
(1-A)[a2 ( Bi+E-3 81) - B2 (an+ Eia)]
= - P3,
duz
(1–A)[a3 ( E1 B+E4 Bi) – Ba (E, 0+ E,a)]
= - P2,
duz
(1-A)[a4 (Bs +E, ) – Ba (as+ E- as)]
=- P1,
du4
(1-A)[as (E, B,) – Bs (EiL, a1)]
( E4)( E-1 8.)
= - Po.
(2.9)
Hence, the linearized equation of Eq.(1.1) about ỹ takes the form
Ym+1+P5Ym +P4Ym–1+P3Ym-2+P2Ym-3+pıym-4+ PoYm-5 = 0,
(2.10)
where po, p1, P2, P3, P4 and p5 are given by (2.9).
The characteristic equation associated with Eq.(2.10) is
18 + psd5+ paXª + p3d3 + p2X² + pid + po = 0,
(2.11)
Transcribed Image Text:2 The local stability of the solutions In this section, the local stability of the solutions of Eq.(1.1) is investigated. The equilibrium point ỹ of Eq.(1.1) is the positive solution of the equation i=1 ỹ = Aỹ + (2.6) E-1 Bi Then, the only positive equilibrium point ỹ of Eq.(1.1) is given by Li=1 (2.7) (1 – A) ( E) 55 provided that A < 1. Nơw, let us introduce a continuous function (0, 0)6 → (0, ∞) which is defined by H : H(uo, ..., u5) = Auo + (2.8) Therefore, it follows that H(u0,...,u5) = A, H(u0,...,us) a1 E(B;u;)] – B1 [E2la;u;)] H(uo,...,u5) H(uo,...,u5) duz H(u0,...,u5) a4 (E-1(Biu;)+Bsus] – Ba [Ei-1(asu;)+agus] H(u0,...,u5) Əug a5 Consequently, we get 8H(ỹ,.î) = A=- P5, duo (1–4)[a1 ( , Bi) – B1 (Ea)] = - P4, (1-A)[a2 ( Bi+E-3 81) - B2 (an+ Eia)] = - P3, duz (1–A)[a3 ( E1 B+E4 Bi) – Ba (E, 0+ E,a)] = - P2, duz (1-A)[a4 (Bs +E, ) – Ba (as+ E- as)] =- P1, du4 (1-A)[as (E, B,) – Bs (EiL, a1)] ( E4)( E-1 8.) = - Po. (2.9) Hence, the linearized equation of Eq.(1.1) about ỹ takes the form Ym+1+P5Ym +P4Ym–1+P3Ym-2+P2Ym-3+pıym-4+ PoYm-5 = 0, (2.10) where po, p1, P2, P3, P4 and p5 are given by (2.9). The characteristic equation associated with Eq.(2.10) is 18 + psd5+ paXª + p3d3 + p2X² + pid + po = 0, (2.11)
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