the man pulls upward with a force F whose direction makes an angle of 30.0° with the ramp (Fig. E4.4). (a) How large a force F is necessary for the component F parallel to the ramp to be 90.0 N? (b) How large will the component F, perpendicular to the ramp be then? Figure E4.4 30.0° T20.0°

University Physics Volume 1
18th Edition
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Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter6: Applications Of Newton's Laws
Section: Chapter Questions
Problem 63P: The contestant now pulls the block of ice with a rope over his shoulder at the same angle above the...
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the nec
4.4 • A man is dragging a trunk up the
loading ramp of a mover's truck. The
ramp has a slope angle of 20.0°, and
the man pulls upward with a force F
whose direction makes an angle of 30.0°
with the ramp (Fig. E4.4). (a) How large a force F is necessary for the
component F parallel to the ramp to be 90.0 N? (b) How large will the
component F perpendicular to the ramp be then?
75.0°
Figure E4.4
30.0
20.0
Transcribed Image Text:the nec 4.4 • A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.0°, and the man pulls upward with a force F whose direction makes an angle of 30.0° with the ramp (Fig. E4.4). (a) How large a force F is necessary for the component F parallel to the ramp to be 90.0 N? (b) How large will the component F perpendicular to the ramp be then? 75.0° Figure E4.4 30.0 20.0
Problem
In the end of the Chapter 4 Problem 4.4 of your book consider that the trunk has mass M travels at a constant velocity along a frictionless inclined and the angles involved
are ej and es, where es corresponds to the angle with respect to the direction of motion and 0j is the angle of the inclined. What are the simplified expressions for the
tension on the rope and the normal force on the trunk in terms of M, g and the angles?
Answer
T =
(6)/
n = (Mg)(
(6)
Os +
Transcribed Image Text:Problem In the end of the Chapter 4 Problem 4.4 of your book consider that the trunk has mass M travels at a constant velocity along a frictionless inclined and the angles involved are ej and es, where es corresponds to the angle with respect to the direction of motion and 0j is the angle of the inclined. What are the simplified expressions for the tension on the rope and the normal force on the trunk in terms of M, g and the angles? Answer T = (6)/ n = (Mg)( (6) Os +
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