The one line diagram of the system and data: Gl and G2:reactance=0.2 p.u ,11kv, 100MVA T1 and T2: reactance =0.05p.u ,11/132 kv L1: reactance=0.216p.u, 132kv L2=0.09p.u, 132kv L3=0.09p.u, 132kv Calculate the fault current when a three phase fault accurs at bus 5 L2 L3 3 T2 4 T1 (G2 L1

The one line diagram of the system and data: Gl and G2:reactance=0.2 p.u ,11kv, 100MVA T1 and T2: reactance =0.05p.u ,11/132 kv L1: reactance=0.216p.u, 132kv L2=0.09p.u, 132kv L3=0.09p.u, 132kv Calculate the fault current when a three phase fault accurs at bus 5 L2 L3 3 T2 4 T1 (G2 L1

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter13: Transmission Lines: Transient Operation

Section: Chapter Questions

Problem 13.1P

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Concept explainers

Types of Thyristors

With four layers of alternating P- and N- materials, a thyristor is a solid-state semiconductor device. It acts as a type of bi-stable switch and it conducts when the gate receives a current trigger and continues to conduct until the voltage is reverse biased across the device or by some means until the voltage is removed. The silicon-controlled rectifier is considered synonymous with thyristors by some sources. Thyristors are defined as more complex by other sources as it contains at least four-layer of alternating N-type and P-type substrate. They find large applications in the control of electrical power supplies, electric motor speed control, and ranging of light dimmers because thyristors can control large amounts of power supplies and voltage with a small device. The circuit symbol of the thyristor is given below.

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The one line diagram of the system and data:
Gl and G2:reactance=0.2 p.u,11kv, 100MVA
T1 and T2: reactance =0.05p.u , 11/132 kv
L1: reactance=0.216p.u, 132kv
L2=0.09p.u, 132kv
L3=0.09p.u, 132kv
Calculate the fault current when a three phase fault accurs at bus 5
L2
L3
3
T2
4
T1
1
G2
L1

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