Question
Asked Sep 19, 2019
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The percent composition by mass of a compound is 76.0% C, 12.8% H, and 11.2% O. The molar mass of this compound is 284.5 g/mol. What is the molecular formula of the compound?

answer choices

C10H6O

C9H18O

C18H36O2

C20H12O2

C16H28O4

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Expert Answer

Step 1

Given,

The percent composition by mass of a compound is 76.0% C, 12.8% H, and 11.2% O.

The molar mass of this compound is 284.5 g/mol.

Molar mass of carbon = 12.0107

Molar mass of hydrogen = 1.008

Molar mass of oxygen = 15.999

Number of moles of carbon is calculated below,
Mass
Moles
Molar mass
76 g
Moles
12g
Moles 6.333
Number of moles of hydrogen is calculated below,
Mass
Moles
Molar mass
12.8 g
Moles
1.008 g
Moles 12.698
Number of moles of oxygen is calculated below
Mass
Moles
=
Molar mass
11.2g
Moles
15.999 g
Moles 0.700
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Number of moles of carbon is calculated below, Mass Moles Molar mass 76 g Moles 12g Moles 6.333 Number of moles of hydrogen is calculated below, Mass Moles Molar mass 12.8 g Moles 1.008 g Moles 12.698 Number of moles of oxygen is calculated below Mass Moles = Molar mass 11.2g Moles 15.999 g Moles 0.700

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Step 2

Therefore,

The ratio of the number of moles of carbon, hydroge...

Divide through by smallest number
6.33
= 9
0.7
С -
C 9
12.7
= 18.14
0.7
н
Н3 18
0.7
0.7
O 1
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Image Transcriptionclose

Divide through by smallest number 6.33 = 9 0.7 С - C 9 12.7 = 18.14 0.7 н Н3 18 0.7 0.7 O 1

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