   # Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymers: a. C 3 H 4 O 2 (acrylic acid, from which acrylic plastics are made) b. C 4 H 6 O 2 (methyl acrylate, from which Plexiglas is made) c. C 3 H 3 N (acrylonitrile, from which Orion is made) ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 73E
Textbook Problem
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## Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymers:a. C3H4O2 (acrylic acid, from which acrylic plastics are made)b. C4H6O2 (methyl acrylate, from which Plexiglas is made)c. C3H3N (acrylonitrile, from which Orion is made)

(a)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in C3H4O2,C4H6O2 and C3H3N compound is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in C3H4O2 compound.

### Explanation of Solution

The atomic weight of carbon (C) is 12.01g/mol . In the compound C3H4O2 , three carbon atoms are present. Hence, mass of carbon in C3H4O2 is,

3×12.01g/mol=36.03g/mol

The atomic weight of oxygen (O) is 16.00g/mol . In the compound C3H4O2 , two oxygen atoms are present. Hence, mass of oxygen in C3H4O2 is,

2×16.00g/mol=32g/mol

The atomic weight of hydrogen (H) is 1.008g/mol . In the compound C3H4O2 , four hydrogen atoms are present. Hence, mass of hydrogen in C3H4O2 is,

4×1.008g/mol=4.032g/mol

The molar mass is the sum of mass of individual atoms present in it. Hence, molar mass of C3H4O2 is calculated as,

36.03g/mol+4.032g/mol+32g/mol=72.053g/mol

Formula

The mass percent of element is calculated as,

Mass%ofelement=MassofelementMolarmassofcompound (1)

Substitute the values of mass of carbon and molar mass of C3H4O2 in the above equation

(b)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in C3H4O2,C4H6O2 and C3H3N compound is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in C4H6O2 compound.

(c)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in C3H4O2,C4H6O2 and C3H3N compound is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in C3H3N compound.

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