The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y the width. S 2x + 2y x – y = 38 Use the method of substitution to solve this system. The corresponding modeling system is = 3 Answer 2 Points E Keypad Keyboard Shortcuts Length of the rectangle = m, Width of the rectangle = m

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter7: Conic Sections And Quadratic Systems
Section7.4: Solving Nonlinear Systems Of Equations
Problem 60E
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The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x = the
length and y = the width.
2x + 2y
x - y
= 38
Use the method of substitution to solve this system.
= 3
The corresponding modeling system is
Answer 2 Points
E Keypad
Keyboard Shortcuts
Length of the rectangle = ||
m,
%23
Width of the rectangle =
m
2021 Hawkes Learning
ere to search
DELL
近
Transcribed Image Text:The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y = the width. 2x + 2y x - y = 38 Use the method of substitution to solve this system. = 3 The corresponding modeling system is Answer 2 Points E Keypad Keyboard Shortcuts Length of the rectangle = || m, %23 Width of the rectangle = m 2021 Hawkes Learning ere to search DELL 近
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