The period of a pendulum varies directly as the square root of the length of the pendulum and inversely as the square root of the acceleration due to gravity. Find the period when the length is 64cm and the acceleration due to gravity is 980 cm per second​ squared if the period is 5π seconds when the length is 289 cm and the acceleration due to gravity is 980 cm per second squared. Write in fraction

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Functions
Section9.CR: Review Problem Set
Problem 74CR: The surface area of a cube varies directly as the square of the length of an edge. If the surface...
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The period of a pendulum varies directly as the square root of the length of the pendulum and inversely as the square root of the acceleration due to gravity. Find the period when the length is 64cm and the acceleration due to gravity is 980 cm per second​ squared if the period is 5π seconds when the length is 289 cm and the acceleration due to gravity is 980 cm per second squared.

Write in fraction

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