3-2.11 The phosphoryl group transfer potentials for glucose-1-phosphate and glucose-6-phosphate are -20.9 kJ/mol and -13.8 kJ/mol, respectively.Part AWhat is the equilibrium constant for the reaction shown below at 25°C?CH₂OHK=SubmitVAZФRequest AnswerНHOO-PO32-Н OHGlucose-1-phosphate?с.НOH ННННОCH₂OPO 2-ННOH НOHН OHGlucose-6-phosphate

Answered: The phosphoryl group transfer…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The standard free energy change for the reaction catalyzed by phosphoglucomutase is -7.1 kJ/mol. Calculate the equilibrium constant for the reaction. Calculate AG at 37°C when the concentration of glucose-1-phosphate is 1-mM and the concentration of glucose-6-phosphate is 25-mM. Is the reaction spontaneous under these conditions? HOCH, -20;POCH, H H H H H H ОН Н НО ОН Н H НО ОН H ОН H. ОН Glucose-l-phosphate Glucose-6-phosphate
Calculate the equilibrium constant for the reaction glucose-1-phosphate + H2O → glucose + H2PO4− at pH 7.0 and 25°C (ΔG°′ = −20.9 kJ · mol−1).
A) Calculate the Gibbs free energy change for the following reaction: Fructose diphosphate If the reaction is performed at 27°C and AH is 1,246 calories and AS is 4 calories/K. Is this a spontaneous or non-spontaneous reaction. Why? Is the reaction endergonic or exergonic? DHAP+ Glyceraldehyde phosphate
The ΔG°′ for hydrolytically removing a phosphoryl group from ATP is about twice as large as the ΔG°′ for hydrolytically removing a phosphoryl group from AMP (−14 kJ · mol−1). Explain the discrepancy.
If the Gibbs free energy change for the reaction; Succinate + FAD →Fumarate + FADH2 is -40KJ/mol at 37° C. Calculate the ratio of FAD: FADH2 in this condition, if [Succinate]=0.75M and [Fumarate]=0.5M at this condition. Half reaction Standard reduction potential (in volts) Fumarate + 2H + 2 e →Succinate 0.031 FAD+2H+ + 2e →FADH2 -0.219
Glucose 1-phosphate is converted into fructose 6-phosphate in two successive reactions. Reaction 1: Glucose 1-phosphate → glucose 6-phosphate AG'° = -7.3 kJ/mol Reaction 2: Glucose 6-phosphate → fructose 6-phosphate AGʻ° = +1.7 kJ/mol Using the values given, calculate the standard free-energy change, AGʻ°, ,for the sum of the two reactions: sum > Sum: Glucose 1-phosphate → fructose 6-phosphate AG'°, kJ/mol sum Calculate the equilibrium constant, K', eq > for the sum of the two reactions. K'e eq II
The standard state free energy of hydrolysis of acetyl phosphate isΔG° = -42.3 kJ/mol. Acetyl-P + H2O acetate + Pi Calculate the free energy change for the acetyl phosphate hydrolysis in a solution of 2 mM acetate, 2 mM phosphate and 3 nM acetyl phosphate.
Given that the standard free-energy change for the reaction glucose + Pi →glucose 6-phosphate is 13.8 kJ/mol, and the standard free-energy change forthe reaction ATP → ADP + Pi is −30.5 kJ/mol, what is the free-energychange for the reaction glucose + ATP → glucose 6-phosphate + ADP?
Given that the AG" values for the hydrolysis of glucose 1-phosphate and glucose 6-phosphate are approximately -21 kJ/mol and –14 kJ/mol, respectively, which statement is true regarding the isomerization shown? glucose 1-phosphate → glucose 6-phosphate O The reaction can likely proceed in either direction and will therefore depend on the concentrations of glucose 1-phosphate and glucose 6-phosphate. O Only the anabolic direction will occur because the free energy change is positive. O The reaction will proceed in both directions simultaneously. This reaction can only proceed in one direction and must be the rate limiting reaction for this point in metabolism.
Calculate the standard free energy change for the following reaction: 3-PG + ATP 1,3-BPG + ADP ---> Given the following standard free energies of hydrolysis: ATP = - 31 kJ/mol 1,3-BPG = - 49.6 kJ/mol 18.6 kJ/mol 80.6 kJ/mol -80.6 kJ/mol 18.6 kJ/mol
G6P(ag) F6P(aq) AG°=+1.7kJ/mol at 25 °C Consider the reaction: Estimate the fraction of F6P (Fructose 6 Phosphate) in equilibrium with G6P (Glucose 6 Phosphate) at 25 °C, where the fraction is defined as [F6P]/([F6P]+[G6P]). Show ALL your work.
[References) The AG" for the reaction ATP + H₂O ADP + P + H+ is -30.5 kJ mol'¹, Other organophosphate species also undergo hydrolysis of the phosphate moiety via a similar reaction. Determine the value of AG for the following reactions and indicate if the reaction will proceed spontaneously in the direction written if the reactants and products are initially in a 1:1 molar ratio. a. ATP + Glucose ADP+ Glucose-1-phosphate AG⁹¹ = kJ mol-1 The reaction is (The hydrolysis reaction for glucose-1-phosphate is Glucose-1-phosphate + H₂0 Glucose + P + H+; AG-20.9 kJ mol ¹.) b. ATP + Glutamate Carbamoyl phosphate + ADP AG The reaction is kJ mol-1 (The hydrolysis reaction for carbamoyl phosphate is Carbamoyl phosphate + H₂0 Glutamate + P, + H+ ; AG¹ = -51.4 kJ mol ¹.) Submit Answer Try Another Version 3 item attempts remaining

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