The pictured system below consisting of the masses m, and m2, the massless cable and the massless pulleys is released at time t = 0. One of the pulleys is fixed in A. The motion of the cable over the pulleys occurs without friction. The cables do not stretch. The system moves under the influence of gravity.
The pictured system below consisting of the masses m, and m2, the massless cable and the massless pulleys is released at time t = 0. One of the pulleys is fixed in A. The motion of the cable over the pulleys occurs without friction. The cables do not stretch. The system moves under the influence of gravity.
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.72P
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Solve (2) please
![The pictured system below consisting of the masses m, and m2, the massless cable and the massless
pulleys is released at time t = 0. One of the pulleys is fixed in A. The motion of the cable over the pulleys
occurs without friction. The cables do not stretch. The system moves under the influence of gravity.
Given:
m1 ; m2 ; m1 >;m2; g
Find:
Using both Newton's and d'Alembert's laws, determine,
1. the positions x,(t) and x2(t) of the masses m, and m2
2. the cable force S(t).
DA
A X2
t = 0
m2
X1
m,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F58c9bc68-0c1e-4565-87f1-69e900edbc74%2Fff0534df-880b-438a-a01a-0f3774941df2%2Fd5m5hi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The pictured system below consisting of the masses m, and m2, the massless cable and the massless
pulleys is released at time t = 0. One of the pulleys is fixed in A. The motion of the cable over the pulleys
occurs without friction. The cables do not stretch. The system moves under the influence of gravity.
Given:
m1 ; m2 ; m1 >;m2; g
Find:
Using both Newton's and d'Alembert's laws, determine,
1. the positions x,(t) and x2(t) of the masses m, and m2
2. the cable force S(t).
DA
A X2
t = 0
m2
X1
m,
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