The position of a 0.30-kg object attached to a spring is described by x (0.27 m) cos(0.7xt) %3D (a) Find the amplitude of the motion. 0.27 (b) Find the spring constant. 1.45 N/m (c) Find the position at t = 0.27 s. %3D 0.223 (d) Find the object's speed at t = 0.27 s. m/s

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
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The position of a 0.30-kg object attached to a spring is described by
(0.27 m) cos(0.7rt)
(a) Find the amplitude of the motion.
0.27
(b) Find the spring constant.
1.45
N/m
(c) Find the position at t = 0.27 s.
0.223
m
(d) Find the object's speed at t = 0.27 s.
m/s
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Transcribed Image Text:The position of a 0.30-kg object attached to a spring is described by (0.27 m) cos(0.7rt) (a) Find the amplitude of the motion. 0.27 (b) Find the spring constant. 1.45 N/m (c) Find the position at t = 0.27 s. 0.223 m (d) Find the object's speed at t = 0.27 s. m/s Need Help? Read It MY
Expert Solution
Step 1

(d)

The position of the object attached to a spring is,

x=0.27cos0.7πt

Solve the above relation for speed of the object.

v=dxdt=ddt0.27cos0.7πt=-0.7π0.27sin0.7πt

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