The position of a 0.30-kg object attached to a spring is described by x = (0.29 m) cos(0.6xt). (Assume t is in seconds.) (a) Find the amplitude of the motion. |0.29 m (b) Find the spring constant. 0.6 Your response differs from the correct answer by more than 10% (c) Find the position of the object at t = 0.25 s. X m (d) Find the object's speed at t = 0.25 s. X m/s

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 13P: A 500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic...
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The position of a 0.30-kg object attached to a spring is described by
X =
(0.29 m) cos(0.6xt). (Assume t is in seconds.)
(a) Find the amplitude of the motion.
0.29
(b) Find the spring constant.
0.6
Your response differs from the correct answer by more than 10%. Double check your calculations. N/m
(c) Find the position of the object at t = 0.25 s.
X m
(d) Find the object's speed at t = 0.25 s.
X m/s
Transcribed Image Text:The position of a 0.30-kg object attached to a spring is described by X = (0.29 m) cos(0.6xt). (Assume t is in seconds.) (a) Find the amplitude of the motion. 0.29 (b) Find the spring constant. 0.6 Your response differs from the correct answer by more than 10%. Double check your calculations. N/m (c) Find the position of the object at t = 0.25 s. X m (d) Find the object's speed at t = 0.25 s. X m/s
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