The potential energy U as a function of position x of an object is given by U(x)=400/x, where U is in joules and x is in meters. The object is released from rest at position x = 30 m and is free to move along the x-axis. When the object has decreased a distance of 10 m from the initial position, the magnitude of the force associated with this potential energy function is:

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A: Given : Wnc = +40 J Wc = -60 J

Q: U(J) 30 20 5 メレ x (m)

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Q: A small object with mass m = 0.0900 kg moves along the +x-axis. The only force on the object is a…

A:

Q: As an object moves from point A to point B only two forces act on it: one force is nonconservative…

A: Given : Wnc = +40 J  Wc = -60 J

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A: This question is based on work done due to constant force.