A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential energy function U(x.y) = (5.8 ) x-(3.6J/m2)y.What are the magnitude and direction of the acceleration of the block when it is at the point (x,y)-(0.300, 0.600)? Option1 Option2 Option3 Option4 Option5 a = 130 m/sa 65.0 m/s?a = 120 m/s2 a=-20.0 m/s² a 6.50 m/s 0 =92 8 = 132 e 83° e 52 0=28°

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 50P: A particle of mass 0.50 kg moves along the x -axis with a potential energy whose dependence on x is...
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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the
potential energy function U(x, y) = (5.8-) x-(3.6J/m²)y.What are the magnitude and direction of
the acceleration of the block when it is at the point (x,y)3(0.300, 0.600)?
Option1
Option2
Option3
Option5
a = 130 m/s² a = 65.0 m/s?a = 120 m/s2 a=-20.0 m/s² a 6.50 m/s
0=92°
Option4
e = 1320
0 830
8=52°
0 = 280
Transcribed Image Text:A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential energy function U(x, y) = (5.8-) x-(3.6J/m²)y.What are the magnitude and direction of the acceleration of the block when it is at the point (x,y)3(0.300, 0.600)? Option1 Option2 Option3 Option5 a = 130 m/s² a = 65.0 m/s?a = 120 m/s2 a=-20.0 m/s² a 6.50 m/s 0=92° Option4 e = 1320 0 830 8=52° 0 = 280
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