The principal stresses at a point in a critical section are sigma_{1} = 60MPa sigma_{2} = 5MPA and sigma_{3} = - 40MPA. The tensile yield strength of material is sigma_{y} = 2 Find the factor of safety of material, According to the maximum shear stress theory. %3D

The principal stresses at a point in a critical section are sigma_{1} = 60MPa sigma_{2} = 5MPA and sigma_{3} = - 40MPA. The tensile yield strength of material is sigma_{y} = 2 Find the factor of safety of material, According to the maximum shear stress theory. %3D

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.4P: Solve the preceding problem if the internal pressure is 3,85 MPa, the diameter is 20 m, the yield...

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

The principal stresses at a point in a critical section are sigma_{1} = 60MPA
sigma_{2} = 5MPA and sigma_{3} = - 40MPA. The tensile yield strength of material is sigma_{y} = 200MPA
Find the factor of safety of material, According to the maximum shear stress theory.

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