Quick ans need in 1hr please 3.A compression test was carried out on a brass cylinder of 32 mm indiameter and guage length of 150 mm.calculate the following:i. The proportional limit stressii. The modulus of elasticityiii. The modulus of resilienceiv. The modulus of toughnessSecant modulus of stress 210 Mpavi. Ultimate compressive strenghtvii. Contraction %Explain the fracture characteristic of test specimenv.viii.300Stress250MPа200150100500.0000.0020.004Strain

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Answered: The proportional limit stress The…

Engineering

Mechanical Engineering

The proportional limit stress The modulus of elasticity The modulus of resilience

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A brass specimen of the circular cross-section is fractured at 151 kN force and the final length of the specimen at fracture is 49 mm. The fracture strength of the specimen is found to be 74 kN/mm2. The percentage of elongation of the specimen is 42 %. Determine the following (i) Diameter of the specimen ii) Initial length of the specimen iii) Stress under an elastic load of 16 kN iv) Young's Modulus if the elongation is 1.6 mm at 16 kN (v) Final diameter if the percentage of reduction in area is 20 % solve: Stress under the elastic load (in N/mm2) = Young's Modulus of the Specimen (in N/mm2) = Final Area of the Specimen at Fracture (in mm) =
A brass specimen of the circular cross-section is fractured at 151 kN force and the final length of the specimen at fracture is 49 mm. The fracture strength of the specimen is found to be 74 kN/mm2. The percentage of elongation of the specimen is 42 %. Determine the following (i) Diameter of the specimen ii) Initial length of the specimen iii) Stress under an elastic load of 16 kN iv) Young's Modulus if the elongation is 1.6 mm at 16 kN (v) Final diameter if the percentage of reduction in area is 20 % solve: Final Diameter of the Specimen after Fracture (in mm) =
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