The pump in Fig. 7.20 delivers water from the lower to the upper reservoir at the rate of 2.0 ft/s. The energy loss between the suction pipe inlet and the pump is 6 lb-ft/lb and that between the pump outlet and the upper reservoir is 12 lb-ft/lb. Both pipes are 6-in Schedule 40 steel pipe. Calculate (a) the pressure at the pump inlet, (b) the pressure at the pump outlet, (c) the total head on the pump, and (d) the power delivered by the pump to the Assume that the level of the lower reservoir is 10 ft above the pump instead of below it. All other data remain the same.

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 The pump in Fig. 7.20 delivers water from the lower to the upper reservoir at the rate of 2.0 ft/s. The energy loss between the suction pipe inlet and the pump is 6 lb-ft/lb and that between the pump outlet and the upper reservoir is 12 lb-ft/lb. Both pipes are 6-in Schedule 40 steel pipe. Calculate (a) the pressure at the pump inlet, (b) the pressure at the pump outlet, (c) the total head on the pump, and (d) the power delivered by the pump to the

Assume that the level of the lower reservoir is 10 ft above the pump instead of below it. All other data remain the same.

101
기
d. The pressure at the inlet to the pump.
c. The power delivered to the oil by the pump.
Discharge pipe
Suction pipe
General Energy Equation
******
Pump
********
FIGURE 7.20 Problems 7.14 and 7.15.
294040 50
tol
S
Transcribed Image Text:101 기 d. The pressure at the inlet to the pump. c. The power delivered to the oil by the pump. Discharge pipe Suction pipe General Energy Equation ****** Pump ******** FIGURE 7.20 Problems 7.14 and 7.15. 294040 50 tol S
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