The quantity of energy Q transferred by heat conduction through an insulating pad in time interval Δt is described by Q/Δt = κAΔT/d, where κ is the thermal conductivity of the material, A is the face area of the pad (perpendicular to the direction of heat flow), ΔT is the difference in temperature across the pad, and d is the thickness of the pad. In one trial to test material as lining for sleeping bags, 86.0 J of heat is transferred through a 3.40-cm-thick pad when the temperature on one side is 37.0°C and on the other side is 2.00°C. In a trial of the same duration with the same temperatures, how much heat will be transferred when more of the material is added to form a pad with the same face area and total thickness 8.41 cm?

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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The quantity of energy Q transferred by heat conduction through an insulating pad in time interval Δt is described by Qt = κAΔT/d, where κ is the thermal conductivity of the material, A is the face area of the pad (perpendicular to the direction of heat flow), ΔT is the difference in temperature across the pad, and d is the thickness of the pad. In one trial to test material as lining for sleeping bags, 86.0 J of heat is transferred through a 3.40-cm-thick pad when the temperature on one side is 37.0°C and on the other side is 2.00°C. In a trial of the same duration with the same temperatures, how much heat will be transferred when more of the material is added to form a pad with the same face area and total thickness 8.41 cm?

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