The reduction half-reaction for a Hall-Heroult electrolytic cell is represented by the following equation. Al³+ + 3e → Al If a current of 10.0A is applied for 5.00 h to the Hall - Heroult electrolytic cell, then the amount of electrons transferred is 5.60 mol 1.87 mol 6.22 x 10-¹ mol 5.18 x 104 mol

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