Q1/The acceleration is defined bythe relation a=(8-0.6 v). Knowingthat the initial velocity is 14 m/s.A/ the velocity at t= 4 s: *14.8 m/s15.67 m/s10.5 m/s22.84 m/s13.39 m/s11.8 m/s17.33 m/sQ1/B/The distance at t=3 s *40.92 mThe velocity at any time25.13 mO V=16.33+0.76e*(-0.7t)O v=13.33+0.67e"(-0.6t)-18.9 mO v=0.67+13.33e^(-0.7t)O V=-13.33-0.6e(t)26.45 mO 16.33-0.67e*(0.6t)42.18 mO Other:13.33 mOO

Answered: Image /qna-images/answer/cc732822-2054-4c09-99e3-440deb69b057.jpg

Answered: the relation a=(8-0.6 v). Knowing that…

the relation a=(8-0.6 v). Knowing that the initial velocity is 14 m/s. A/ the velocity at t= 4 s: * 14.8 m/s 15.67 m/s 10.5 m/s 22.84 m/s 13.39 m/s 11.8 m/s 17.33 m/s Q1/B/The distance at t=3 s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

Q1/The acceleration is defined by
the relation a=(8-0.6 v). Knowing
that the initial velocity is 14 m/s.
A/ the velocity at t= 4 s: *
14.8 m/s
15.67 m/s
10.5 m/s
22.84 m/s
13.39 m/s
11.8 m/s
17.33 m/s
Q1/B/The distance at t=3 s *
40.92 m
The velocity at any time
25.13 m
O V=16.33+0.76e*(-0.7t)
O v=13.33+0.67e"(-0.6t)
-18.9 m
O v=0.67+13.33e^(-0.7t)
O V=-13.33-0.6e(t)
26.45 m
O 16.33-0.67e*(0.6t)
42.18 m
O Other:
13.33 m
OO

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