The resultant force ER and its two components F₁ and F₂ acting on a machine element are directed as shown. a) With the aid of a simple diagram, explain how a concurrent force system is formed and how it relates to the resultant force. [CO1/PO1/C2] b) Given F₁ = 200 N, (i) express E in the rectangular coordinates, (ii) determine the magnitude of and FR, and (iii) find the reaction at the support O for static equilibrium of the machine element. [CO2/PO1/C4] 16; c) Without any calculation, assess the effect that F₂ will have on FR if is directed vertically upward. [CO3/PO1/C6]. F₁-187.9 i-116.4 iN: (ii) F₂ = 342 N: FR = 411 N. Q=- FRI FR Figure

Elements Of Electromagnetics
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1-3 The resultant force ER and its two components F₁ and
F₂ acting on a machine element are directed as shown.
a) With the aid of a simple diagram, explain how a
concurrent force system is formed and how it relates
to the resultant force. [CO1/PO1/C2]
b) Given F₁ = 200 N, (i) express E in the rectangular
coordinates, (ii) determine the magnitude of F₂ and
FR, and (iii) find the reaction at the support O for
static equilibrium of the machine element.
[CO2/PO1/C4] 16:
c) Without any calculation, assess the effect that F₂ will
have on FR if F2 is directed vertically upward.
[CO3/PO1/C6]
[b) (i) E₁ =187.9 i-116.4 i N; (ii) F2 = 342 N; FR = 411 N, (iii) Q=-ER]
FR
Figure
F₁
F₂
36°
20⁰
P1-3
25⁰
X
Transcribed Image Text:1-3 The resultant force ER and its two components F₁ and F₂ acting on a machine element are directed as shown. a) With the aid of a simple diagram, explain how a concurrent force system is formed and how it relates to the resultant force. [CO1/PO1/C2] b) Given F₁ = 200 N, (i) express E in the rectangular coordinates, (ii) determine the magnitude of F₂ and FR, and (iii) find the reaction at the support O for static equilibrium of the machine element. [CO2/PO1/C4] 16: c) Without any calculation, assess the effect that F₂ will have on FR if F2 is directed vertically upward. [CO3/PO1/C6] [b) (i) E₁ =187.9 i-116.4 i N; (ii) F2 = 342 N; FR = 411 N, (iii) Q=-ER] FR Figure F₁ F₂ 36° 20⁰ P1-3 25⁰ X
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