The salt content was extracted from a 12.0000g junk food sample. The extract was diluted to 100.00mL. From this solution, 15.00mL was taken and required 23.75mL of a 0.08943M AgNO solution to reach the endpoint. What is the percentage by mass of salt as NaCI (58.45 g/mol) in the junk food sample? (Answer: 6.897% NaCl)
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The salt content was extracted from a 12.0000g junk food sample. The extract was diluted to 100.00mL. From this solution, 15.00mL was taken and required 23.75mL of a 0.08943M AgNO solution to reach the endpoint. What is the percentage by mass of salt as NaCI (58.45 g/mol) in the junk food sample? (Answer: 6.897% NaCl)
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- PLEASE ANSWER ONLY NUMBERS 4 AND 5 Shan wanted to extract 3.12g of a new compound from 150mL of water using chloroform. She determined that the solubility of the compound is 0.019g/L and 0.276g/L in water and in chloroform, respectively. Determine: Kd value of the compound between chloroform and water. Amount of the compound that would be extracted if Shan performed a one-step extraction using 75.0mL of chloroform Amount of the compound that would be extracted after the first step if Shan performed a two-step extraction with 37.5mL of chloroform each Amount of the compound that would be extracted after the second step Percent efficiency of the two-step extraction compared to the one-step extractionYou have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt.( Answer in mM) a)If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be B)What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h?What's the differences between two questions? Q1) How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations. -->Tap water 8Oz = 8 x 0.0296L = 0.2368L Hardness = 66.73ppm = 66.73mg/L CaCO3 1L has 66.73mg CaCO3 0.2368L has 66.73mg x 0.2368 = 15.8017mg MW of CaCO3 = 100g/mol MW of Ca = 40g/mol 100g CaCO3 has 40gf of Ca 15.8017mg CaCO3 has 40/100 x 15.8017mg Ca We would ingest 6.321mg of Ca. Q2) What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations. --> 66.73mg/1150mg x 100 = 5.80% My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it? CaCO3 = 100g/mol, Ca = 40g/mol 100g CaCO3 has 40g Ca. 66.73 CaCO3 has 40/100 x 66.73mg Ca Ca = 26.70mg 26.70mg/1150mg x 100 = 2.32%