The sample should include men and women.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 26PFA
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Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference
between proportions of men and women who own smartphones. Assume that you want 95% confidence that your error is no more than
0.02.
AClick the icon to view the discussion of sample size.
The sample should include
men and
women.
(Type whole numbers.)
Sample size discussion
The sample size needed to estimate the difference between two population
proportions to within a margin of error E with a confidence level of 1-a can be
found by using the following expression:
P191
P292
E=Za12
n2
Replace n1
and
n, by n in the preceding formula (assuming that both samples
have the same size) and replace each of p,, 91, P2, and q, by 0.5 (because their
values are not known). Solving for n results in this expression:
2
/2
2E?
Print
Done
Transcribed Image Text:Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 95% confidence that your error is no more than 0.02. AClick the icon to view the discussion of sample size. The sample should include men and women. (Type whole numbers.) Sample size discussion The sample size needed to estimate the difference between two population proportions to within a margin of error E with a confidence level of 1-a can be found by using the following expression: P191 P292 E=Za12 n2 Replace n1 and n, by n in the preceding formula (assuming that both samples have the same size) and replace each of p,, 91, P2, and q, by 0.5 (because their values are not known). Solving for n results in this expression: 2 /2 2E? Print Done
Expert Solution
Given

Margin or error = 0.02

z-critical value at 0.05 = 1.96

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