The Scanner class .next() method will read
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1) The Scanner class .next() method will read:
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a. one word b. a character c. a line of text d. an integer
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- Hi, I am struggling a bit with this problem. (This is in Java by the way.) Provided code: import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String userText; // Add more variables as needed userText = scnr.nextLine(); // Gets entire line, including spaces. /* Type your code here. */ }}can you please write in java.util.scanner form ,can you please make it so i can copy and past it int[] numbers = {345, 632, 675, 157, 834, 294, 832};1. Write a method to find its highest value. 2. Write a method to find its lowest value. 3. Write a method to find its total value.JAVA What is the output of the following code sequence when the user successively enters 3, 5, and -1? Scanner scan = new Scanner(System.in); int i = 0; while(i != -1) { System.out.println("RED"); i = scan.nextInt(); } System.out.println("END");
- there are 2 errors in this code can you fix it for me? public class Exercise09_10 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a, b, c: "); double a = input.nextDouble(); double b = input.nextDouble(); double c = input.nextDouble(); QuadraticEquation equation = new QuadraticEquation(a, b, c); double discriminant = equation.getDiscriminant(); if (discriminant < 0) { System.out.println("The equation has no roots"); } else if (discriminant == 0) { System.out.println("The root is " + equation.getRoot1()); } else // (discriminant >= 0) { System.out.println("The roots are " + equation.getRoot1() + " and " + equation.getRoot2()); } } }a. Which class is used to deal with the string subscript out of range. b. Which class is used when a length greater than the maximum allowed for a string object occurs?c. Which class is used to deal with errors that can be detected only during program execution?Consider the code below that prompts the user to input values for x and for y. It then prints the bigger value contained in the variables x and y. import java.util.Scanner; public class SmallestInt { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Enter a value for x:"); int x = scan.nextInt(); System.out.println("Enter a value for y:"); int y = scan.nextInt(); if (x >= y) System.out.println("The bigger value was " + x); else System.out.println("The bigger value was " + y); } } Modify the code above so that it prompts the user to enter a third value for a variable z. Then rewrite the logic above so that the program prints out the biggest value contained in x, y, and z.
- Please Code in JAVA. Type the code out neatly. Add comments . (No need for long comments). Dont add any unnecesary code or comments. Do what the attached file says. And call it a day. Thanks !Question: Write a program that calculates and displays the conversion of an entered number of dollars into currency denominations—20s, 10s, 5s, and 1s. Example output: $452 converted is 22 $20s, 1 $10s, 0 $5s, and 2 $1s. Here's what i put: import java.util.Scanner; class Dollars { public static void main(String[] args) { // Write your code here Scanner inputDevice = new Scanner(System.in); final int ORIGNIAL_CASH = inputDevice.nextInt(); int twenties; int tens; int fives; int ones; twenties = ORIGNIAL_CASH / inputDevice.nextInt(); tens = twenties % inputDevice.nextInt(); fives = tens / inputDevice.nextInt(); ones = (ORIGNIAL_CASH / 20 / 10 / 1); System.out.println("$" + ORIGNIAL_CASH + " converted is " + twenties + " $" + "20s, " + tens + " $" + "10s, "+ fives + " $" + "5s, " + ones + " $" + "1s" ); } } Results $432 converted is 21 $20s, 1 $10s, 0 $5s, and 2 $1s…Need help with step 4. Below are my work for steps 1 and 2 and 3 are the screenshot codes. THIS IS MY CODE FOR STEP 1 - import java.util.Scanner;//to readinputpublic class Main{ public static void main(String[] args) { String s1,s2,s3;//to store 3 names Scanner sc = new Scanner(System.in);//to read input //reading 3 names from user System.out.println("Enter three names :"); s1=sc.next(); s2=sc.next(); s3=sc.next(); System.out.println("Descending order:"); //printing 3 names, in descending order if(s1.compareTo(s2)>=0 && s2.compareTo(s3)>=0)//if s1>=s2>=s3 { System.out.println(s1+"\n"+s2+"\n"+s3); } else if(s1.compareTo(s3)>=0 && s3.compareTo(s2)>=0)//if s1>=s3>=s2 { System.out.println(s1+"\n"+s3+"\n"+s2); } else if(s2.compareTo(s1)>=0 && s1.compareTo(s3)>=0)//if s2>=s1>=s3 { System.out.println(s2+"\n"+s1+"\n"+s3); } else if(s2.compareTo(s3)>=0 &&…
- Please modify my program so that the output will print like what is in the picture. Thank you in advance.import java.util.*; public class sales { public static void main(String[] args) { Scanner kbd = new Scanner(System.in); String[] names; String[] address; String[] age; // String[] age; int n = 0; boolean successfulRead=false; do { try { System.out.println("How many names will be sorted: "); n = Integer.parseInt(kbd.nextLine()); if (n >=0 ) { successfulRead = true; } else { System.out.println("The amount cannot be a negative amount"); successfulRead = false; } } catch (NumberFormatException…JAVA - Please produce both a product.java file and a productprinter.java file (tester) Implement a class Product. A product has a name and a price, for example new Product("Toaster", 29.95). Supply methods getName, getPrice, and reducePrice. Supply a program ProductPrinter that makes two products, prints each name and price, reduces their prices by $5.00, and then prints the prices again.create a Word document that contains the pseudocode, flowchart, and test plan for both projects (Programming Project 4(import java.util.Scanner; public class Exercise06_25 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter time in milliseconds: "); long milliseconds = input.nextLong(); System.out.println(convertMillis(milliseconds)); } public static String convertMillis(long millis) { // Calculate the number of hours, minutes, and seconds long hours = millis / 3600000; millis %= 3600000; long minutes = millis / 60000; millis %= 60000; long seconds = millis / 1000; // Return the formatted string return hours + ":" + minutes + ":" + seconds; }}) and Programming Project 5(import java.util.Scanner; public class Exercise06_37 { public static void main(String[] args) { Scanner input = new Scanner(System.in);…