Question
Asked Oct 21, 2019
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The specific heat of a certain type of metal is 0.128 J/(g⋅∘C). What is the final temperature if 305 J of heat is added to 57.1 g of this metal, initially at 20.0 ∘C?

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Expert Answer

Step 1

The amount of heat gained or lost by a metal in a chemical process is related to its specific heat in accordance with expression (1), in which, q is the amount of heat, m is the mass of the metal, s is the specific heat, T1 is the final temperature, and T2 is the final temperature.

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q ms(T-T) (1)

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Step 2

The final temperature of the given metal ...

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305 J 57.1 g x 0.128 J/g°C(T2-20 °C) 305 J (T,-20 °C) 57.1 g x 0.128 J/g°C T (41.7+20) °C =61.7°C

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