The standard molar enthalpy of formation of diborane, B2H6(g), cannot be determined directly because the compound cannot be prepared by the reaction of boron and hydrogen. It can be calculated from other enthalpy changes, however.The following enthalpy changes can be measured. 4 B(s) + 3O2(g) → 2 B2O3(s) ΔrH∘ = -2543.8 kJ/mol-rxn H2(g) +1/2 O2(g) → H2O(g) ΔrH∘ = -241.8 kl/mol-rxn B2H6(g) + 3O2(g) → B2O3(s) + 3 H2O(g) ΔrH∘ = -2032.9 kJ/mol-rxn (a) Show how these equations can be added together to give the equation for the formation of B2H6(g) from B(s) and H2(g) in their standard Assign enthalpy changes to each reaction. (b) Calculate Δf H∘ for B2H6(g). (c) Draw an energy level diagram that shows how the various enthalpies in this problem are related. (d) Is the formation of B2H6(g) from its elements exo- or endothermic?

Chemistry & Chemical Reactivity
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Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
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Problem 81GQ: The standard molar enthalpy of formation of diborane, B2H6(g), cannot be determined directly because...
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The standard molar enthalpy of formation of diborane, B2H6(g), cannot be determined directly because the compound cannot be prepared by the reaction of boron and hydrogen. It can be calculated from other enthalpy changes, however.The following enthalpy changes can be measured.

4 B(s) + 3O2(g) → 2 B2O3(s)

ΔrH = -2543.8 kJ/mol-rxn

H2(g) +1/2 O2(g) → H2O(g)

ΔrH = -241.8 kl/mol-rxn

B2H6(g) + 3O2(g) → B2O3(s) + 3 H2O(g)

ΔrH = -2032.9 kJ/mol-rxn

(a) Show how these equations can be added together to give the equation for the formation of B2H6(g) from B(s) and H2(g) in their standard Assign enthalpy changes to each reaction.

(b) Calculate Δf H for B2H6(g).

(c) Draw an energy level diagram that shows how the various enthalpies in this problem are related.

(d) Is the formation of B2H6(g) from its elements exo- or endothermic?

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