The steam reforming reaction me thane follows this quemical equation= CHycg) + HzO g)→ Co g) + 3Hz cg) Aptl = +194 k]lmol <> lies far to the reactant side with Of 7.20 x 1o23. TO s:gnificant a movat of the desired hydrogen 9t very high Const ant qt A+ 298 K the reaction very Small equililon um constant ob tain gas product temperatuas , , the reac tion is operated wLat is 4he equilibrium T100 x? ans wer as a hum loer with no decimal places

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.33PAE: The following experimental data were obtained for the reaction of \'I14* and NOf in acidic solution....
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o4 me thane follows this quemical
The steam retorming reaction
equation=
CHycg) t HzOg→ cog) + 3 Hz ca) Apti= + 194 kjlnol
- + 194
->
lies far to the reactant side with
7.20 x 10 23. TO
the desired hydrogen
9f uery high
Const ant at
A+
298 K
the reaction
e quililori um
Significant a movnt of
a very
Small
consdant
of
ob tain
gas product, the reae tion is operated
temperatuas.
wLat is 44e e quilibrium
T100 K?
ans wer as a hum loer with no decimal places
Transcribed Image Text:o4 me thane follows this quemical The steam retorming reaction equation= CHycg) t HzOg→ cog) + 3 Hz ca) Apti= + 194 kjlnol - + 194 -> lies far to the reactant side with 7.20 x 10 23. TO the desired hydrogen 9f uery high Const ant at A+ 298 K the reaction e quililori um Significant a movnt of a very Small consdant of ob tain gas product, the reae tion is operated temperatuas. wLat is 44e e quilibrium T100 K? ans wer as a hum loer with no decimal places
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