The tetraethyl lead Pb(C2H5)4 in a 25.00 mL sample of aviation gasoline was shaken with 15.00 mL of 0.02179 M I2. (Hint: one mole of I2 reacts with one mole of the tetraethyl lead). After the reaction was complete, the unused I2 was titrated with 7.37 mL of 0.02959 M thiosulfate solution. Calculate the weight of Pb(C2H5)4 (MW = 323.4

The tetraethyl lead Pb(C2H5)4 in a 25.00 mL sample of aviation gasoline was shaken with 15.00 mL of 0.02179 M I2. (Hint: one mole of I2 reacts with one mole of the tetraethyl lead). After the reaction was complete, the unused I2 was titrated with 7.37 mL of 0.02959 M thiosulfate solution. Calculate the weight of Pb(C2H5)4 (MW = 323.4

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter18: Representative Metals, Metalloids, And Nonmetals

Section: Chapter Questions

Problem 115E: A mixture of xenon and ?uorine was heated. A sample of the white solid that formed reacted with...

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A mixture of xenon and ?uorine was heated. A sample of the white solid that formed reacted with hydrogen to yield 81 ml of xenon (at STP) and hydrogen ?uoride, which was collected in waiter, giving a solution of hydro?uoric acid. The hydro?uoric acid solution was titrated, and 68.43 mL of 0.3172 M sodium hydroxide was required to reach the equivalence point. Determine the empirical formula for the white solid and write balanced Chemical equations for the reactions involving xenon.
The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH. After cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate the amount of ethyl acetate (88.11 g/mol) in the original sample in grams.
1. An acid solution is prepared by dissolving 19.264 grams of pure KHC2O4.H2C2O4.2H2O in water and diluting to exactly 900 ml. Fifty milliliters (50.00 mL) of this solution are neutralized by 35.00 ml. of KOH solution. What is the normality of each solution? 2. What mass of Ca(OH)2 is present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M HNO3? The balanced chemical equation is as follows: 2HNO3 + Ca(OH)2 → Ca(NO3)2 + 2H2O ; Balanced.
An unknown 36% v/v monohydroxide reagent has a density of 1.8 g/mL. Zeus wanted to determine the identity of this base, so he transferred a 90.916-mL aliquot of the base to a 1.0 L volumetric flask and diluted it up to mark. He then titrated the base solution and found out that its concentration is 1.0 M.a. What is the molarity of the base solution after dilution? b. If this 1.00M solution is used in the analysis of PLA (Polylactic Acid) plastics for lactic acid (H2Lactate) titration, what is its concentration in titer mg LA/mL titrant? (Lactic Acid: 90.08 g/mol)c. What is the molarity of the unknown monohydroxide reagent?d. What is the molar mass of the unknown monohydroxide reagent?(Density of H2O = 0.99707 g/mL)Hint: Mass of solution = mass of solvent + mass of solutee. What is the identity of the unknown monohydroxide reagent?
The ethyl acetate concentration in a alcoholic solution was determined by diluting a 10.00 mL sample to 100.00 mL. A 20.00 mL portion of diluted solution was refluxed with 40.00 mL of 0.04672 M KOH. Ater cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate the amount of ethyl acetate (88.11 g mol) in the original sample in grams.
The formaldehyde content of a pesticide was determined by weighing 0.9327 g of the liquid sample into a flask containing 50.0 mL of 0.08624 M NaOH and 50 mL of 3% H2O2. It was heated then cooled. After cooling, the excess base was titrated with 27.8 mL of 0.06325 M H2SO4. Calculate the percentage of HCHO in the sample.
An analyte solution was prepared using 1.1278 g of a diprotic acid and 25.0 mL of distilled water. A 5.0 mL aliquot was then taken and diluted to 50.0mL. During titration, it required 19.4 mL of a 0.0356 M standardized NaOH solution to reach the end point. a.) What is the molarity of the undiluted analyte solution? b.) What is the molecular weight of the diprotic acid?
For breakfast, the nihilistic Rick Sanchez ate 100 g of cereal mixed with 20 g of milk. A 1.500 g sample of the same cereal was analyzed using the Kjeldahl method, and the liberated NH3 was distilled into 50 mL of a 0.0227 M HCl solution, and back-titrated with 2.85 mL of 0.0112 M NaOH solution. A 1.100 g sample of milk was also analyzed, and the liberated NH3 was distilled into 55 mL of a 0.0234 M HCl solution, and back-titrated with a 3.10 mL of 0.0121 M NaOH. Use the values: MM N=14.07 g/mol. meat= 6.25 dairy= 6.38 cereal= 5.70 What is the % protein in the cereal sample? What is the % protein in the milk sample?
For breakfast, the nihilistic Rick Sanchez ate 100 g of cereal mixed with 20 g of milk. A 1.500 g sample of the same cereal was analyzed using the Kjeldahl method, and the liberated NH3 was distilled into 50 mL of a 0.0227 M HCl solution, and back-titrated with 2.85 mL of 0.0112 M NaOH solution. A 1.100 g sample of milk was also analyzed, and the liberated NH3 was distilled into 55 mL of a 0.0234 M HCl solution, and back-titrated with a 3.10 mL of 0.0121 M NaOH. Use the values: MM N=14.07 g/mol. meat= 6.25 dairy= 6.38 cereal= 5.70 1. What is the % protein in the cereal sample? a. 5.90% protein b. 10.21% protein c. 11.80% protein d. 20.42% protein 2. What is the % protein in the milk sample? a. 5.90% protein b. 10.21% protein c. 11.80% protein d. 20.42% protein 3. How many grams of protein did Rick consume over-all? a. 3.749 g b. 7.942 g c. 5.901 g d. 10.21 g
A 14.00 mL sample of sulfuric acid is diluted to 50.00 mL. A 10.00 mL aliquot is titrated to a phenolphthalein endpoint with 42.80 mL of 0.1020 M NaOH. What is the molarity of the original solution.
Use the following atomic masses (in g/mol): Mg = 24.31; H = 1; S = 32.06; O = 16; Na = 23; Cl = 35. 45; Ca = 40.08; C = 12.01; N = 14.01; Mg = 24.31 5.A sample of Chlorpheniramine Maleate (99.82%) weighing 0.502g was assayed by non-aqueous titrimetry and was found to be equivalent to 22.2mL of perchloric acid. Calculate for the normality of perchloric acid. Each mL of 0.1N perchloric acid is equivalent to 19.54mg of Chlorpheniramine Maleate.
A 0.05002 gram sample of methyl amine (CH3NH2: MW = 31.07 g/mol; Kb = 4.35 x 10-4) was mixed with 100.0 mL of HCl. Calculate the molar concentration of the acid if 5.55 mL of 0.1057 M KOH was needed to back-titrate the unreacted acid.