1A)The total flux through the Gaussian sphere indicated with the dashed line is0 = qleo-The solid substance is made of conducting material.What is the charge in cavity B?O a) -gb) +qO c) +29d) -2gB)When a completely ionized helium atom moves across a potential difference, itsenergy changes by AU=(-1.18x10^-15) J.What is the value of the potential difference?Provide your answer in volts, use scientific notation. Use three significant figures inyour response.Ignore D2L's comment about "highest possible power", present your answer in formatX.YZ*10^N.Note: Your answer is assumed to be reduced to the highest power possible.Your Answer:х10AnswerunitsC)Two point charges, q1 =4.0 nC and q2 =-5.0 nC are located at A =(0.5,-1.0)m andB =(-2.6,-3.6)m, respectively.Calculate the electric potential due to these point charges at P =(-5.2,-2.7)m.Express your answer in volts, use appropriate symbols. Express your answer roundedto have at least one digit after the decimal, do not use scientific notation. Using moresignificant figures will not be considered incorrect, using fewer may result in errorsdue to rounding.Your Answer:Answerunits

In this question we have to determine the magnitude of Charge in cavity B. Note: Due to company…

The total flux through the Gaussian sphere indicated with the dashed line is $ = qleo- The solid substance is made of conducting material. What is the charge in cavity B? B +2g O a) -g O b) +g O c) +2q d) -2q

The total flux through the Gaussian sphere indicated with the dashed line is $ = qleo- The solid substance is made of conducting material. What is the charge in cavity B? B +2g O a) -g O b) +g O c) +2q d) -2q

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 60P: An uncharged conductor with an internal cavity is shown in the following figure. Use the closed...

See similar textbooks

Similar questions

In which of the following contexts ran Gausss law not be readily applied to find the electric field? (a) near a long, uniformly charged wire (b) above a large, uniformly charged plane (c) inside a uniformly charged ball (d) outside a uniformly charged sphere (e) Gausss law can be readily applied to find the electric field in all these contexts.
A uniformly charged spherical shell with positive surface charge density contains a circular hole in its surface. The radius r of the hole is small compared with the radius R of the sphere. What is the electric field at the center of the hole? Suggestion: This problem can be solved by using the principle of superposition.
An uncharged conductor with an internal cavity is shown in the following figure. Use the closed surface S along with Gauss' law to show that when a charge q is placed in the cavity a total charge q is induced on the inner surface of the conductor. What is the charge on the outer surface of the conductor? Figure 6.46 A charge inside a cavity of a metal. Charges at the outer surface do not depend on how the charges are distributed at the inner surface since E field inside the body of the metal is zero.
Suppose the electric field of Quick Quiz 15.7 is tilted 60 away from the positive z-direction. Calculate the magnitude of the flux through the same area. (a) 0 (b) 10.0 N m2/C (c) 20.0 N m2/C (d) More information is needed
A nonconducting, thin plane sheet of charge carries a uniform charge per unit area of 5.20 C/m2 as in Figure 15.30. (a) Find the electric field at a distance of 8.70 cm from the plate. (b) Explain whether your result changes as the distance from the sheet is varied.
7 - A long cylindrical shell with inner radius R1 and outer radius R2 has an electric charge Q evenly distributed over its entire volume. Away from the ends, a small tunnel is drilled through the shaft in such a way that its effect on distribution symmetry can be neglected. Discuss the subsequent movement of an electron abandoned at rest in one of the ends of the tunnel.
The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. a)Given that the oil drop is 1.2 μm in radius and has a density of 905 kg/m3, find the weight of the drop in N. b)If the drop has a single excess electron, find the electric field strength needed to balance its weight.
2. If there are more lines going out of the Gauss surface than there are lines going into the Gauss face, yes What can be concluded about the total charge contained within the Gaussian surface?
Discuss the role that symmetry plays in the application of Gauss' Law. Give examples of continuous charge distributions in which Gauss' Law is useful and not useful in determining the elctric field.
A gold nucleus emanates an elecric field, holding all its electrons in place. How strong is the electric field by a single electron from its outermost orbital, located at 136 pm? How fast is it moving on its circular orbit, assuming it has a hypothetical plane orbit? How much kinetic energy is gained by the electron?
10 - If we are interested in finding the electric field associated with the following charge distributions: A charged hemisphere of radius R, a small cylinder of length L, a small flat plate with sides A and B, we could use Gauss' Law for the electrostatics? Discuss.
An infinite straight line of charge of linear density λ lies along the x axis from negative infinity to positive infinity.a) Find the electric field and some point at perpendicular distance r away from the line of charge.b) Calculate the electric field if the line of charge has a linear density of λ = 2 nC/m, at a perpendiculardistance of 10 cm.