The two shafts of a speed-reducer unit are subjected to couples of magnitude M1 = 10 Ib-ft and M2 = 5 Ib-ft, respectively. Replace the two couples with a single equivalent couple, specifying its magnitude and the direction of its axis. M, OM = 10.18 Ib-ft, x = 26.57, 6y = 90.00, 02 = 63.43 OM = 11.18 Ib-ft, 8x = 26.57, 6y = 90.00, 02 = 63.43 OM = 12.18 Ib ft, x = 26.57, 0y = 90.00, 82 = 63.43 OM = 10.18 Ib ft, Ox = 63.43, 0y = 90.00, 0z = 26.57 OM = 11.18 Ib-ft, 8x = 63.43, 6y = 90.00, 02 = 26.57 OM = 12.18 Ib ft, 0x = 63.43, 8y = 90.00, 0z = 26.57

Elements Of Electromagnetics
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QUESTION 4
The two shafts of a speed-reducer unit are subjected to couples of magnitude M1 = 10 Ib-ft and M2 = 5 lb-ft, respectively. Replace the two couples with a single equivalent couple, specifying its magnitude and the direction of
its axis.
O M = 10.18 Ib-ft, 0x = 26.57, 0y = 90.00, 02 = 63.43
O M = 11.18 Ib-ft, 0x = 26.57, 0y = 90.00, 02 = 63.4
O M = 12.18 Ib-ft, 6x = 26.57, 0y = 90.00, 02 = 63.43
O M = 10.18 Ib-ft, 6x = 63.43, 0y = 90.00, 02 = 26.57
O M = 11.18 Ib-ft, Ox = 63.43, 6y = 90.00, 02 = 26.57
O M = 12.18 Ib-ft, 8x = 63.43, 0y = 90.00, 02 = 26.57
Transcribed Image Text:QUESTION 4 The two shafts of a speed-reducer unit are subjected to couples of magnitude M1 = 10 Ib-ft and M2 = 5 lb-ft, respectively. Replace the two couples with a single equivalent couple, specifying its magnitude and the direction of its axis. O M = 10.18 Ib-ft, 0x = 26.57, 0y = 90.00, 02 = 63.43 O M = 11.18 Ib-ft, 0x = 26.57, 0y = 90.00, 02 = 63.4 O M = 12.18 Ib-ft, 6x = 26.57, 0y = 90.00, 02 = 63.43 O M = 10.18 Ib-ft, 6x = 63.43, 0y = 90.00, 02 = 26.57 O M = 11.18 Ib-ft, Ox = 63.43, 6y = 90.00, 02 = 26.57 O M = 12.18 Ib-ft, 8x = 63.43, 0y = 90.00, 02 = 26.57
Expert Solution
Step 1

Given data:

M1=Mz=10 lb.ftMy=0M2=Mx=5 lb.ft

Need to determine the equivalent couple and its directions.

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