The van der Waals equation compensates for non-ideal behavior of gases by taking into account intermolecular forces and the volume of the gas molecules. For CO, a = 1.505 L²atm/mol? and b = 0.03985 L/mol. Use the van der Waals equation to determine the pressure, in atmospheres, of 1.50 moles of CO gas in a 3.00 L flask at 25.0°C. Remember the gas constant, R, is 0.08206 L·atm/mol· K. %3D P + a (V – nb ) = nRT V.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter6: The Gaseous State
Section: Chapter Questions
Problem 6.128QE
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The van der Waals equation compensates for non-ideal
behavior of gases by taking into account intermolecular forces
and the volume of the gas molecules.
1.505 L'atm/mol? and b = 0.03985 L/mol. Use the
For CO, a =
van der Waals equation to determine the pressure, in
atmospheres, of 1.50 moles of CO gas in a 3.00 L flask at
25.0°C. Remember the gas constant, R, is 0.08206 L·atm/mol·
K.
in
(V- nb ) = nRT
V
P+ a
Transcribed Image Text:The van der Waals equation compensates for non-ideal behavior of gases by taking into account intermolecular forces and the volume of the gas molecules. 1.505 L'atm/mol? and b = 0.03985 L/mol. Use the For CO, a = van der Waals equation to determine the pressure, in atmospheres, of 1.50 moles of CO gas in a 3.00 L flask at 25.0°C. Remember the gas constant, R, is 0.08206 L·atm/mol· K. in (V- nb ) = nRT V P+ a
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